计算二进制数据的出现次数

Question

我需要在二进制文件中计算十六进制字符串0xFF 0x84 0x03 0x07的出现次数，没有太多的麻烦...是否有一种从linux命令行中获取此数据的快速方法，或者我应该编写专用代码来执行此操作？

Answer 1

If your version of grep takes the -P parameter, then you can use grep -a -P , to search for an arbitrary binary string inside a binary file. This is close to what you want:

grep -a -c -P '\xFF\x84\x03\x07' myfile.bin

• -a ensures that binary files will not be skipped

• -c outputs the count

• -P specifies that you pattern is a Perl regular expression, which allows strings to contain hex characters in the above \\xNN format.

Unfortunately, grep -c will only count the number of "lines" the pattern appears on, even if it appears multiple times on a line. (I'm not sure why that would be a desirable feature).

To get the exact number of occurrences with grep , it seems you need to do:

grep -a -o -P '\xFF\x84\x03\x07' myfile.bin | wc -l

grep -o separates out each match onto its own line, and wc -l counts the lines. Note that this depends on the fact that your binary string contains no linebreaks.

Answer 2

use hexdump like

hexdump -v -e '"0x" 1/1 "%02X" " "' <filename> | grep -oh "0xFF 0x84 0x03 0x07" |wc -w

hexdump will output binary file in the given format like 0xNN

grep will find all the occurrences of the string without considering the same ones repeated on a line

wc will give you final count

Answer 3

did you try grep -a ?

from grep man page:

-a, --text
              Process a binary file as if it were text; this is equivalent to the --binary-files=text option.

Answer 4

怎么样：

$ hexdump a.out | grep -Ec 'ff ?84 ?03 ?07'

Answer 5

This doesn't quite answer your question, but does solve the problem when the search string is ASCII but the file is binary:

cat binaryfile | sed 's/SearchString/SearchString\n/g' | grep -c SearchString

Basically, 'grep' was almost there except it only counted one occurrence if there was no newline byte in between, so I added the newline bytes.