使用grep查找动态文本

Question

Need help with a bash script. We are modifying our database structure, the problem is we have many live sites that have pre-written queries referencing the current database structure. I need to find all of our scripts with references to MySQL tables. Here is what I started:

grep -ir 'from' /var/www/sites/inspection.certifymyshop.com/ > resultsList.txt

I am trying to grep through our scripts recursively and export ALL table names found to a text file, we can use the "->from" and the "->join" prefixes to help us:

->from('databaseName.table_name dtn')  // dtn = table alias

OR

->join('databaseName.table_name dtn')  // dtn = table alias

I need to find the database and table name within the single quotes (ie databaseName.table_name). I also need to list the filename this was found in underneath or next to the match like so:

someDatabaseName.someTableName | /var/www/sites/blah.com/index.php | line 36

Answer 1

Try doing this :

grep -oPriHn -- "->(?:from|join)\('\K[^']+" . |
    awk -F'[ :]' '{print $3, "|", $1, "| line " $2}'

If this fits your needs, I can explain the snippet more as well.

Answer 2

The one problem you have with only using grep is removing the from, join or whatever identifying prefix from the result. To fix this we can also use sed

grep -EHroi -- '->(from|join)\('\''[^'\'' ]*' /path/to/files | sed -re 's/:.*(from|join)\('\''/:/g'

You could also use sed alone in a for loop

for i in `find /path/to/files -type f -print`
do
   echo $i
   sed -nre 's/^.*->(from|join)\('\''([^'\'' ]*)['\'' ].*$/\2/gp' $i
done

Edit: The above for loop breaks with filenames with spaces so here's the previous sed statement using find

find ./ -type f -exec sh -c "echo {} ; sed -nre 's/^.*->(from|join)\('\''([^'\'' ]*)['\'' ].*$/\2/gp' \"{}\" ;" \;