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Question

I have controller that loads a customer details view which includes the name of the customer, email, fax,phoneNo. ...etc i want the user of the system when types in the form of the customer name to check if this customer exists in the database and instantly to show his contact details in the forms of email, fax , ...etc is this doable without having to load the view once again ?

Answer 1

1.You can do this by having a array of customers when you loading the view, when user types the name you can check this value with array you have. It is to be noted you have to make js array of the php array you get from the controller.

2.Use ajax. Simple and dynamic.

Answer 2

Hope this will help you.

Controller: [I am writing only the functions.]

public function customer_details() {
       $data['base_url'] = base_url();
       $data['somedata'] = 'somevalue';
       $this->load->view('customerDetailsView',$data);
}
public function ajax_fetchDetails() {
       $customerName = $this->input->post('cname');
       $this->load->model('customerDetails');
       $cdetails = $this->customerDetails->fetchdetails($customerName);
       if(!empty($cdetails)) {
          echo json_encode($cdetails);
       }
       else echo '0'; //Handle it in view.
}

---

Model: [Write your own Query]

 Select * from `customerdetails` where `name` like $customerName limit = 1; 

---

View: customerDetailsView [I am writing only what should appear in the tag]

<!--For the following script to work you'll have to use jquery library.-->
  <script type="text/javascript">
    $("#fetchbtn").onclick( function(event) {
        var name = jQuery.trim($("#cname").val()); //Fetch the customer name enter in the input field.
        if(name != '') // Check for empty condition
        {
            $.ajax({
            type: "POST", url:"<?php echo $base_url.'<CONTROLLER NAME>/ajax_fetchDetails'; ?>",
            data:{cname:name},
                success: function(result) {
                    if(result != '0') {
                        var customerDetails = JSON && JSON.parse(result) || $.parseJSON(result); // Parse the JSON encoded customer details into string.
                        var email = customerDetails.email, fax = customerDetails.fax; //... So on
                        $("#email").val(email); $("#fax").val(fax); //... So on
                    }
                }
            });
        }
    });
  </script>

... So on Untill all the details are covered.

 <!--For the following script to work you'll have to use jquery library.--> <script type="text/javascript"> $("#fetchbtn").onclick( function(event) { var name = jQuery.trim($("#cname").val()); //Fetch the customer name enter in the input field. if(name != '') // Check for empty condition { $.ajax({ type: "POST", url:"<?php echo $base_url.'<CONTROLLER NAME>/ajax_fetchDetails'; ?>", data:{cname:name}, success: function(result) { if(result != '0') { var customerDetails = JSON && JSON.parse(result) || $.parseJSON(result); // Parse the JSON encoded customer details into string. var email = customerDetails.email, fax = customerDetails.fax; //... So on $("#email").val(email); $("#fax").val(fax); //... So on } } }); } }); </script> 

The only disadvantage here is, if two customers have same name only the 1st customer's details will be fetched. To avoid this, you'll have to maintain unique username for each customer.