python从文件中的行创建列表

Question

I need to create a list of strings for each line in a file. 我需要为文件中的每一行创建一个字符串列表。

Example: 例：

This is my file.
These are examples.

would create: ['This', 'is', 'my', 'file'] ['These', 'are', 'examples'] 会创建：['This'，'is'，'my'，'file'] ['These'，'are'，'examples]]

I need to do this because I am trying to translate a file into a pig latin file. 我需要执行此操作，因为我正在尝试将文件转换为猪拉丁文件。

Answer 1

Split each line in the file along the space character and retrieve it as a list. 沿着空格字符分割文件中的每一行，并将其作为列表检索。

f = open('filename.txt', 'r')
li = [line.split() for line in f]

Answer 2

Try this: 尝试这个：

res = []
with open(filename, 'r') as f:
    for line in f:
         res.append(line.split())

OR: 要么：

map(str.split, open(filename, 'r'))

If you need to get rid of dots: 如果您需要去除点：

res = []
with open(filename, 'r') as f:
    for line in f:
         res.append(line.strip('.').split())

Answer 3

You can also use the readLines 您也可以使用readLines

f = open('file.txt', 'r')
lines = [line.split(' ') for line in f.readlines()]