C，获取unsigned char以使用ascii 2表

Question

so all i want is to get this to display the ascii 2 table using an unsigned char array. heres what i have and whats not working:

unsigned char digits[100];
int i=0;
while (i<=100)
{
printf("\n%c",digits[i]+48);
i++;
}

pretty simple code so far. not working at all though.

any suggestions?

Answer 1

The problem is that digits[i] is not initialized.

If all you're doing is displaying the ASCII table, you don't need the array at all.

Answer 2

There is no need to use an array. This will work:

int i=0;
while (i<=100){
    printf("\n%c", i + '0');
    i++;
}

Also, your array is not initialized.

Answer 3

#include <stdio.h>

int main(void){
    unsigned char digits[100] = { 1,0,2,4 };
    int i=0;

    while (i<100){
        printf("\n%c",digits[i++]+'0');
    }

    printf("\ninput number:");
    fgets(digits, 100, stdin);

    i=0;
    while(digits[i] && digits[i] != '\n')
        printf("\n%c", digits[i++]);

    return 0;
}