如何从代码而不是 Google App Engine 上的文件呈现 django 模板

Question

I am writing a Google App Engine webapp that renders some html to a Django template. I want to either render the template using either a file or just some json thats very similar to that in file. Is it possible to use Django to render this to a file that is read in and stored in database? The oldAPI.HTML is just an old version of api.html but with some small changes. Rendering Django to the api-html file works fine.

I understand that you can't store files on GAE, how can i dynamically use Django to render to HTML stored in memory?

path = ""
oldAPI = APIVersion().get_by_key_name(version)
if oldAPI is None:
    path = os.path.join(os.path.dirname(__file__), "api.html")
template_values = {
            'responseDict': responseDict,
            }
        if path:
            self.response.out.write(template.render(path, template_values))
        else:
            self.response.out.write(template.render(oldAPI.html,template_values))

Answer 1

In order to render a template 'in memory', there are a few things you'll need to do:

App Engine Setup

First of all, you'll need to ensure that everything is set up correctly for Django. There's a lot of information on the Third-party libraries page , but I'll include it here for your benefit.

In main.py , or (whatever your script handler is), you'll need to add the following lines:

import os
os.environ['DJANGO_SETTINGS_MODULE'] = 'settings'

from google.appengine.dist import use_library
use_library('django', '1.2') # Change to a different version as you like

Don't forget to include django in your app.yaml :

libraries:
    - name: django
      version: "1.2"

Code Setup

Second of all, you'll need to create a Template object, as denoted in the Google App Engine template documentation . For example:

from google.appengine.ext.webapp import template

# Your code...
template_string = "Hello World"
my_template = template.Template(template_string)

# `context` is optional, but will be useful!
# `context` is what will contain any variables, etc. you use in the template
rendered_output = template.render(context)

# Now, do what you like with `rendered_output`!

Answer 2

您可以仅使用template.Template(my_text)从 Django 中的文本实例化模板。

Answer 3

不幸的是，没有（内置）方法可以这样做，但是您可以从函数google.appengine.ext.webapp.template._load_user_django （GAE with Python 2.5）或google.appengine.ext.webapp.template._load_internal_django （ GAE with Python 2.7) 并像 GAE 源代码一样编写您自己的包装器覆盖设置和渲染。