如何在单选按钮单击事件上隐藏/显示输入框

Question

I want to hide and show input field on radio button click event my HTML is

<input type="radio" id="abc" name="abc1" checked = "checked" value="Experienced" />
<label> Experienced </label>  
<input type="radio" id="xyz" name="xyz1" checked = "checked"  value="Fresher" />
<label>Fresher</label>  
<input type="text"  name="cardno" id="tyx" /><br />
<p > Number</p>

What I want is when radio button with value="Fresher" is clicked the input box name="cardno" should be hidden.

I tried to solve this by using jQuery but it is not working.

$(document).ready(function () {
    $("input[name$='abc1']").click(function () {
        var value = $(this).val();
        if (value == 'Experianced') {
            $("#tyx").show();
        } else if (value == 'Fresher') {
            $("#tyx").hide();
        }
    });

Can any body help me how to solve this?

Answer 1

name of your radio button should be same to check on click event or make array name of your radio button

like below code

<input type="radio" id="abc" name="abc1" checked = "checked" value="Experienced" />
<label> Experienced </label>  
<input type="radio" id="xyz" name="abc1" checked = "checked"  value="Fresher" />
<label>Fresher</label>  
<input type="text"  name="cardno" id="tyx" /><br />
<p > Number</p>

and then create function like

$(document).ready(function () {
$("input[name$='abc1']").click(function () {
    var value = $(this).val();
    if (value == 'Experianced') {
        $("#tyx").show();
    } else if (value == 'Fresher') {
        $("#tyx").hide();
    }
});

please reply if i can help you more..

Answer 2

change the spelling to Experienced

you used

if (value == 'Experianced')

Answer 3

Besides the typo in Experienced , try setting up a click event for each radio button:

 $(document).ready(function() {
   $('input[name="abc1"][value="Experienced"]').click(function() {
     $("#tyx").show();
   });
   $('input[name="xyz1"][value="Fresher"]').click(function() {
     $("#tyx").hide();
   });
 });

Note:

You can simplify your selectors to use ids with:

$('#abc')

and

$('#xyz')

Answer 4

Fix with:

$(document).ready(function () {
  $("input[type='radio']").click(function () {
    var value = $(this).val();
    if (value == 'Experianced') {
        $("#tyx").show();
    } else if (value == 'Fresher') {
        $("#tyx").hide();
    }
  });
});

Answer 5

Html:

<input type="radio" id="abc" name="jobtype" checked = "checked" value="Experienced" />
<label> Experienced </label>  
<input type="radio" id="xyz" name="jobtype" checked = "checked"  value="Fresher" />
<label>Fresher</label>  
<input type="text"  name="cardno" id="tyx" /><br />
<p > Number</p>

Radio buttons of same group should have same name

Js:

$(document).ready(function () {
   $("input[name='jobtype']").click(function () {
      var value = this.value;
      if (value == 'Experienced') {
        $("#tyx").show();
      } 
     else{
        $("#tyx").hide();
      }
   });
});