连接两个表mysql，一对多关系

Question

I have two tables:

Points ->

id           bigint(20)   NO   PRI  NULL   auto_increment
created_at   datetime     NO        NULL   
ip           varchar(255) NO        NULL   
item_id      bigint(20)   NO   MUL  NULL   
updated_at   timestamp    YES       NULL   

and Items ->

id           bigint(20)    NO  PRI  NULL   auto_increment
author       varchar(255)  NO       NULL   
created_at   datetime      NO       NULL   
description  varchar(255)  NO       NULL   
link         varchar(255)  NO       NULL   
source       varchar(255)  NO       NULL   
title        varchar(180)  NO       NULL   
url_encoded  varchar(255)  NO  UNI  NULL   
updated_at   timestamp     YES      NULL   

I want to join them hopefully in one query so I will get item.* and the total of how many points are relative to them. I also want to do this only for the items that has any points created for them in the last 24 hours.

This is my query so far:

SELECT `items`.*, COUNT(points.item_id) as points
FROM `items`
INNER JOIN `points` ON `items`.`id` = `points`.`item_id`
WHERE `points`.`created_at` > '2013-03-16 16:00:14'
ORDER BY points DESC
LIMIT 30;

Unfortunately it gives me only one row when it should be two with two points when it should be one. In my database there is two items and one point for each of them. Please help me fix this and understand how I can improve my query to get both the results.

Answer 1

You need to use GROUP BY to explain what groupings to count based on. Without GROUP BY you just get a single group of the entire result set, as you saw.

In standard SQL it is necessary to include in the GROUP BY clause every non-aggregate expression that's included in the SELECT clause, but MySQL lets you get away with not doing this, allowing an expression like the following. (At least, when not in strict mode; I'm not sure if strict mode strengthens this requirement to match standard SQL)

SELECT `items`.*, COUNT(1) AS points
FROM `items` INNER JOIN `points` ON `items`.`id` = `points`.`item_id`
WHERE ...
GROUP BY `items`.`id`

Assuming that items.id is the primary key of this table, and so it won't appear in more than one row of items , this should have the desired effect.

Once you introduce GROUP BY it's important to understand the difference between the WHERE and HAVING clauses. The former applies the condition before the group and aggregates are applied, while the latter applies afterwards . This means you must use HAVING if you want to do a conditional based on that count; the WHERE clause in your initial example will apply before the aggregate, so the result will be the count of points created after the given date.

Answer 2

SELECT i.*, count(*) AS point_ct
FROM   items  i
JOIN   points p ON p.item_id = i.id
GROUP  BY i.id
HAVING MAX(created_at) >= DATE_SUB(CURDATE(), INTERVAL 1 day)
ORDER  BY point_ct DESC
LIMIT  30;

I quote the manual concerning the GROUP BY clause :

MySQL extends the use of GROUP BY to permit selecting fields that are not mentioned in the GROUP BY clause. If you are not getting the results that you expect from your query, please read the description of GROUP BY found in
Section 12.17, “Functions and Modifiers for Use with GROUP BY Clauses” .

Standard SQL would require to list all ungrouped SELECT items in GROUP BY .
However, the standard also defines that "functionally dependent" columns are covered automatically. Since we are grouping by id which is the primary key , this ends up to be standard SQL after all (except for LIMIT 30 , which would be FETCH FIRST 30 ROWS ONLY in standard SQL).

Answer 3

Create a table link. With the fields id , itemid , pointsid

Inputs:

Row1: 1, items-id1, points-id-1
Row2: 2, items-id-1, points-id-2
Row3: 3, items-id-1, points-id-3

SELECT * FROM points, field WHERE tablelink.itemid=items.id AND tablelink.pointsid=points.id;

One item has many points.