使用ubuntu在C ++中使用std :: stoi的问题

Question

I am receiving a compile error when I try to compile the simple program below.

error: 'stoi' was not declared in this scope

I've tried to include both #include <string> and #include <string.h> and I still am having those issues. I am using Ubuntu and I cannot remember how I installed g++ but I am sure it was using the apt-get install g++ command, so I do not know what version of g++ or the C++ libraries I am using.

#include <iostream>
#include <fstream>
#include <string.h>

using namespace std;

struct Data
{
    string fname;
    string lname;
    int age;
};

int main()
{
    bool toContinue = true;
    Data data;
    string buffer;
    do
    {
        try
        {
            getline(cin,data.fname);
            getline(cin,data.lname);
            getline(cin,buffer);
            data.age = stoi(buffer);
            cout<<data.fname<<" ";
            cout<<data.lname<<" ";
            cout<<data.age<<endl;
        }
        catch(std::invalid_argument)
        {
            cerr<<"Unable to parse integer";
        }
    }while(toContinue);

    return 0;
}

My goal is to be able to use exception handling in case the user enters junk for any of the variables.

Answer 1

If you take a look at the documentation , you'll see that it was introduced in C++11. You'll have to compile your code with the -std=c++11 option to enable those features because code isn't compiled as C++11 by default.

Drew commented saying that if you are using C++03, you can use

boost::lexical_cast<int>(buffer)

Answer 2

事实证明我需要它才能使它工作......

g++ -std=c++0x ./main.cpp