简体   繁体   English

如何在 xAxis 上格式化时间使用 d3.js

[英]how to format time on xAxis use d3.js

According the demo on http://bl.ocks.org/mbostock/3883245根据http://bl.ocks.org/mbostock/3883245上的演示

I don't know how format time on xAxis我不知道如何在 xAxis 上格式化时间

this is my code : js:这是我的代码:js:

var data = [{
            "creat_time": "2013-03-12 15:09:04",
            "record_status": "ok",
            "roundTripTime": "16"
        }, {
            "creat_time": "2013-03-12 14:59:06",
            "record_status": "ok",
            "roundTripTime": "0"
        }, {
            "creat_time": "2013-03-12 14:49:04",
            "record_status": "ok",
            "roundTripTime": "297"
        }, {
            "creat_time": "2013-03-12 14:39:06",
            "record_status": "ok",
            "roundTripTime": "31"
        },{
            "creat_time": "2013-03-12 14:29:03",
            "record_status": "ok",
            "roundTripTime": "0"
    }];
    var margin = {top: 20, right: 20, bottom: 30, left: 50};
    var width = 960 - margin.left - margin.right;
    var height = 500 - margin.top - margin.bottom;
    var parseDate = d3.time.format("%Y-%m-%d %H:%M:%S").parse;
    var x = d3.time.scale()
        .range([0, width]);

    var y = d3.scale.linear()
        .range([height, 0]);

    var xAxis = d3.svg.axis()
        .scale(x)
        .orient("bottom");

    var yAxis = d3.svg.axis()
        .scale(y)
        .orient("left");

    var line = d3.svg.line()
        .x(function(d) { return x(d.creat_time); })
        .y(function(d) { return y(d.roundTripTime); });


    var svg = d3.select("body").append("svg")
        .attr("width", width + margin.left + margin.right)
        .attr("height", height + margin.top + margin.bottom)
      .append("g")
        .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

    data.forEach(function(d) {
        d.creat_time = parseDate(d.creat_time);
        d.roundTripTime = +d.roundTripTime;
    });

    x.domain(d3.extent(data, function(d) { return d.creat_time; }));
    y.domain(d3.extent(data, function(d) { return d.roundTripTime;}));

    svg.append("g")
          .attr("class", "x axis")
          .attr("transform", "translate(0," + height + ")")
          .call(xAxis);

    svg.append("g")
          .attr("class", "y axis")
          .call(yAxis)
          .append("text")
          .attr("transform", "rotate(-90)")
          .attr("y", 6)
          .attr("dy", ".71em")
          .style("text-anchor", "end")
          .text("return time(ms)");

    svg.append("path")
          .datum(data)
          .attr("class", "line")
          .attr("d", line);

this is svg:这是 svg:在此处输入图片说明

In svg , time is 12-hour clock ,but in my data time is 24-hour clock .在 svg 中,时间是 12 小时制,但在我的数据中时间是 24 小时制。 how to keep the same format on svg and data?如何在 svg 和数据上保持相同的格式?

Any help is appreciated.任何帮助表示赞赏。 (ps:I hope you don't mind my English,it's so bad.) (ps:我希望你不要介意我的英语,它太糟糕了。)

You can use the tickFormat function on the axis object as below您可以在轴对象上使用 tickFormat 函数,如下所示

var xAxis = d3.svg.axis()
    .scale(x)
    .orient("bottom")
    .tickFormat(d3.time.format("%H"));

The %H specifies hour (24-hour clock) as a decimal number [00,23] . %H hour (24-hour clock) as a decimal number [00,23]指定hour (24-hour clock) as a decimal number [00,23] Check this link D3 time formatting for more information检查此链接D3 时间格式以获取更多信息

You can check out a working example in this tributary 24hr time example您可以在这个支流24 小时时间示例中查看一个工作示例

The accepted answer is indeed correct, but in my case, I needed the flexibility for the formats to adjust to different scales (think zooming), but also to ensure the 24hr clock is used.接受的答案确实是正确的,但就我而言,我需要灵活地调整格式以适应不同的比例(想想缩放),同时还要确保使用 24 小时时钟。 The key is to define a multi-resolution time format .关键是定义一个多分辨率的时间格式 See the Documentation page for details.有关详细信息,请参阅文档页面。

My code:我的代码:

var axisTimeFormat = d3.time.format.multi([
    [".%L", function(d) { return d.getMilliseconds(); }],
    [":%S", function(d) { return d.getSeconds(); }],
    ["%H:%M", function(d) { return d.getMinutes(); }],
    ["%H:%M", function(d) { return d.getHours(); }],
    ["%a %d", function(d) { return d.getDay() && d.getDate() != 1; }],
    ["%b %d", function(d) { return d.getDate() != 1; }],
    ["%B", function(d) { return d.getMonth(); }],
    ["%Y", function() { return true; }]
 ]);

var xAxis = d3.svg.axis()
    .scale(x)
    .orient("bottom")
    .tickFormat(axisTimeFormat);

I want to add this link to an awesome demo page.我想将此链接添加到一个很棒的演示页面。 It is a playground when you can choose what a format specifier do you need for your case.当您可以选择您的案例需要什么格式说明符时,这是一个游乐场。 It is very useful when you do not remember/know what a format specifier you should pass to your d3.timeFormat function.当您不记得/不知道应该传递给d3.timeFormat函数的格式说明符时,它非常有用。

I also want to notice, that if you have d3 version 4, you should use d3.timeFormat function, instead of d3.time.format .我还想注意,如果你有 d3 版本 4,你应该使用d3.timeFormat函数,而不是d3.time.format

In v4,在 v4 中,

...
var scaleX = d3.scaleTime().range([0, width]);
var axisBottom = d3.axisBottom(scaleX)
                   .ticks(d3.timeMinute, 10); // Every 10 minutes
...

Note that use d3.timeMinute - not d3.timeMinutes请注意,使用d3.timeMinute - 而不是d3.timeMinutes

For a multi-resolution time format in d3 v4 and above, d3.time.multi has been deprecateed.对于 d3 v4 及更高版本中的多分辨率时间格式d3.time.multi已被弃用。 Instead, define the formats yourself and use a ternary to detect the correct time, using time intervals .相反,自己定义格式并使用三元来检测正确的时间,使用时间间隔

var formatMillisecond = d3.timeFormat(".%L"),
    formatSecond = d3.timeFormat(":%S"),
    formatMinute = d3.timeFormat("%I:%M"),
    formatHour = d3.timeFormat("%I %p"),
    formatDay = d3.timeFormat("%a %d"),
    formatWeek = d3.timeFormat("%b %d"),
    formatMonth = d3.timeFormat("%B"),
    formatYear = d3.timeFormat("%Y");

function multiFormat(date) {
  return (d3.timeSecond(date) < date ? formatMillisecond
      : d3.timeMinute(date) < date ? formatSecond
      : d3.timeHour(date) < date ? formatMinute
      : d3.timeDay(date) < date ? formatHour
      : d3.timeMonth(date) < date ? (d3.timeWeek(date) < date ? formatDay : formatWeek)
      : d3.timeYear(date) < date ? formatMonth
      : formatYear)(date);
}

When calling an time interval like d3.timeDay(date) , it will floor the current date to the day, week and so on.当调用像d3.timeDay(date)这样的时间间隔时,它会将当前日期d3.timeDay(date)为天、周等。

If the floored date is equal to the current date, then d3.timeSecond(date) < date will be false.如果d3.timeSecond(date) < date日期等于当前日期,则d3.timeSecond(date) < date将为假。 But if it's smaller (that means, you could floor the date) then it's true and we use the formatter.但是如果它更小(这意味着,你可以把日期打倒)那么它是真的,我们使用格式化程序。

In practice:在实践中:

var d = new Date(2020,1,2) // 2020-02-02T00:00

// floor to nearest second
d3.timeSecond(d) // 2020-02-02T00:00, date gets floored but is equal to date 
                 // after flooring, since it already was :00 seconds
d3.timeSecond(d) < d // equal so false, move on to next precision

// ...
// floor to nearest month
d3.timeMonth(d) // 2020-02-01T00:00, date gets floored to months
d3.timeMonth(d) < d // floored date is now smaller, so true, and use month formatter

Code from d3-time-format .来自d3-time-format 的代码。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM