[英]Insert same row multiple times within SQL table based on unique value in field 1
I currently have a table where column 1 is a unique identifier for the remaining columns and I need to insert a new value into the table for each unique identifier. 我目前有一个表,其中第1列是其余列的唯一标识符,我需要为每个唯一标识符在表中插入一个新值。 The example is as follows:
示例如下:
Column 1 Column 2 Column 3 10 Address True 10 City False 10 State True 20 Address True 20 City True 20 State True
I need to insert a new row based upon each unique identifier in Column 1, like so: 我需要根据第1列中的每个唯一标识符插入新行,如下所示:
Column 1 Column 2 Column 3 10 Address True 10 City False 10 State True *10 NEW NEW* 20 Address True 20 City True 20 State True *20 NEW NEW*
For some reason, the SQL script for the quick lookup and insert is just escaping me on a Monday morning. 由于某种原因,用于快速查找和插入的SQL脚本只是在星期一的一个星期一逃离我。 Any help would be appreciated.
任何帮助,将不胜感激。
Thanks! 谢谢!
insert into table-name
(Column1, Column2, Column3)
select Column1, 'NEW', 'NEW*' from table-name group by Column1
You can alternatively use a distinct in the sub-select, but I have started switching to group by, which can be more flexible if I want to change a query to count or something. 您也可以在子选择中使用非重复,但是我已经开始切换为分组依据,如果我想更改查询以进行计数或其他操作,可以更加灵活。
You can try at variant of Marlin Pierce's suggestion of: 您可以尝试Marlin Pierce的以下建议:
INSERT INTO [table-name]
([Column 1], [Column 2], [Column 3])
SELECT [Column 1], 'NEW', 'NEW*' from [table-name] where [Column 2] = 'Address' group by [Column 1];
This creates a single new row for each of your existing rows. 这将为您的每个现有行创建一个新行。
See the SqlFiddle for executable sample. 有关可执行示例,请参见SqlFiddle 。
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