Linux：查找文件中文件路径的总文件大小

Question

I have a file containing some file paths like:

./file1
./dir/file2
./dir3/dir4/fil3
etc

How can i find the total filesize of all of them? I know about "du" for getting the filesize of single file but no idea how to use a file.

Thank you

Answer 1

you can use du to give total size of multiple files

 cat file | tr "\n" "\0" | du -ch --files0-from=- | tail -n1

Use awk for getting file size

 cat file | awk  '{system("ls -l " $0)}' | awk '{ TOTAL += $5} END { print TOTAL}'

Answer 2

GNU coreutils du only suggestion

EDIT: the named option --files0-from is a GNU extension, so this suggested solution won't work with any non GNU coreutils du version. As you don't semm to have it the awk version posted by Vivek Goel is the one you should try instead.

You already answered your own question. Using du is the key. The "missing" option you're looking for might be this one found in the manual pages. (man du)

--files0-from=F
summarize disk usage of the NUL-terminated file names specified in file F; If F is - then read names from standard input

Usage would be like this:

tr "\n" "\0" <file-list | du --files0-from=-