[英]PHP passing parameters to function strange behaviour
I have this function in Utils.php
我在
Utils.php
具有此功能
function GenerateMonthlyReport($connection, $month, $year, $objSheet)
{
$months = array("Enero", "Febero", "Marzo", "Abril", "Mayo", "Junio" ,"Julio", "Agosto", "Septiembre", "Octubre", "Noviembre", "Diciembre");
$fromDate = $year . "-" . $month . "-01";
$toDate = "";
if ($month != 12)
$toDate = $year . "-" . ($month+1) . "-01";
else
$toDate = ($year+1) . "-01-01";
etc..
}
Then in another file createReport.php
i call this function using $_POST
parameters like this 然后在另一个文件
createReport.php
我使用$_POST
参数调用此函数
include "Utils.php";
include "Connect.php";
require_once('PHPExcel/Classes/PHPExcel.php');
checkLogin();
// Connect to Db
$connection = openDb();
// Input Data
$month = mysqli_real_escape_string($connection, $_POST["month"]);
$year = mysqli_real_escape_string($connection, $_POST["year"]);
$objPHPExcel = CreateEmptyWorkbook();
$objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, "Excel2007"); // create the writer
$objSheet = $objPHPExcel->getActiveSheet();
GenerateMonthlyReport($connection, $month, $year, $objSheet);
Problem: the parameters $year
and $month
that i am passing to the function GenerateMonthlyReport are null
inside the function. 问题:我传递给函数GenerateMonthlyReport的参数
$year
和$month
在函数内部为null
。
But if i do something like this: 但是,如果我做这样的事情:
GenerateMonthlyReport($connection, "3", "2013", $objSheet);
they are passed correctly. 他们通过正确。
If i do a echo of $year
and $month
variables, they display values!! 如果我对
$year
和$month
变量进行回显,它们将显示值!
Also: This strange behaviour only happens when i submit the Form from a Mobile Device. 另外:仅当我从移动设备提交表单时,才会发生这种奇怪的行为。 It does not happen from a PC browser.
它不是通过PC浏览器发生的。
EDIT: here is the Form HTML code: 编辑:这是表单HTML代码:
<form id="reportForm" action="/service/createMonthlyReport.php" method="post">
<table border="1">
<tr>
<td>
Seleccione Período
</td>
<td>
<label>Mes</label><br/>
<select id="monthM" name="month" >
<?php for ($i=1; $i<=12; $i++) :?>
<option value="<?php echo $i; ?>" <?php echo date("n") != $i ? "" : "selected" ?>>
<?php echo $monthName = date("M", mktime(0, 0, 0, $i, 10)); ?>
</option>
<?php endfor; ?>
</select>
</td>
<td>
<label>Anio</label><br/>
<select id="yearM" name="year" >
<?php for ($i=-5; $i<=5; $i++) :?>
<?php $yearData = (date("Y") + $i); ?>
<option value="<?php echo $yearData; ?>" <?php echo date("Y") != $yearData ? "" : "selected" ?>>
<?php echo $yearData; ?>
</option>
<?php endfor; ?>
</select>
</td>
<td>
<input type="submit" value="Descargar Reporte Mensual" id="submitBtn" class="crearBtn" />
</td>
</tr>
</table>
</form>
openDB code: openDB代码:
function openDb() {
$sever = "myserver";
$database_name = "dbname";
$user = "user";
$pass = "mypass";
$connection = new mysqli($server, $user, $pass, $database_name) or die("DB connection failed!");;
$connection->set_charset("utf8");
mysqli_query($connection, 'SET NAMES utf8');
mysqli_query($connection, 'SET CHARACTER SET utf8');
return $connection;
}
Your DB encoding is UTF-8, but you avoid characters above 128 in your code by using HTML entities like í
您的数据库编码为UTF-8,但是通过使用
í
这样的HTML实体í
代码中的128个以上的字符í
. 。 I wonder if some ISO 8859-1 in your UTF-8 workflow could be breaking PHP or one of its extensions.
我不知道您的UTF-8工作流程中的某些ISO 8859-1是否会破坏PHP或其扩展之一。 Make sure you have the proper
header()
for UTF-8, and that everything (eg, hidden form variables) is properly UTF-8 encoded. 确保您具有适用于UTF-8的适当的
header()
,并且所有内容(例如,隐藏的表单变量)均经过正确的UTF-8编码。
Anyway, a variable (two in your case) that is null
when it shouldn't be, could be the result of a wrong reference count. 无论如何,一个变量(在您的情况下为两个)在不应该为
null
情况下可能是错误的引用计数的结果。 References are the low level mechanism by which a variable's value is not copied when it is assigned to another variable, but both variables point to the same value, which has a reference count of 2 (or more). 引用是一种低级机制,在将变量的值分配给另一个变量时,该机制不被复制,但是两个变量都指向相同的值,该值的引用计数为2(或更大)。 If, eg, the reference count is not incremented on assignment, but is decremented when a variable goes out of scope, it could become 0 when it should be 1, and the value is erroneously freed.
例如,如果引用计数在赋值时未增加,但在变量超出范围时减小,则当应为1时可能变为0,并且错误地释放了该值。
I think I have already seen a reference count bug. 我想我已经看到了引用计数错误。 It could have been in a database extension (possibly the
sybase
extension, but I'm not sure). 它可能在数据库扩展中(可能是
sybase
扩展,但我不确定)。 If so, it was probably in a *_fetch_*()
function. 如果是这样,它可能在
*_fetch_*()
函数中。
Try to take out pieces of your code. 尝试取出您的代码片段。 Try leaving out the DB calls (including
checkLogin()
, I guess), and/or the PHPExcel
part, and/or others, before getting to the function where you have the problem ( GenerateMonthlyReport()
). 在进入有问题的函数(
GenerateMonthlyReport()
)之前,尝试checkLogin()
数据库调用(包括checkLogin()
,和/或PHPExcel
部分和/或其他)。
Check if you have PHP references ( &
) in your code. 检查代码中是否包含PHP引用(
&
)。 If so, try to do without them (they are not bad in themselves, but being complicated at the low level, they are more likely to trigger a bug of the above kind). 如果是这样,请尝试在没有它们的情况下进行操作(它们本身并不坏,但是在较低级别上比较复杂,它们更有可能触发上述类型的错误)。
In order to rule out name collisions, try also the following: rename year
and month
to year0
and month0
in the form and in $_POST
, $year
and $month
to $year1
and $month1
in the main, and $year
and $month
to $year2
and $month2
in GenerateMonthlyReport()
. 为了排除名称冲突,尝试以下方法:重命名
year
和month
至year0
和month0
在形式和$_POST
, $year
和$month
至$year1
和$month1
为主,和$year
和$month
在GenerateMonthlyReport()
为$year2
和$month2
。
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