Windows批处理文件 - 检查JAVA_HOME是否包含java 7

Question

有没有办法在Windows批处理文件中确定JAVA_HOME环境系统变量是否包含Java 7？

Answer 1

Since you have tagged your question as batch-file , I assume you want to do this in a batch file.

Batch file to check this

@echo off
"%JAVA_HOME%"\bin\java -version:1.7 -version > nul 2>&1
if %ERRORLEVEL% == 0 goto found
echo NOT FOUND
goto end

:found
echo FOUND
:end

I have just made the batch file print FOUND if the java in %JAVA_HOME% is java 7 or print NOT FOUND if it's not java 7. You can tweak the batch file for your needs.

java -version:1.7 returns a success(0) to the shell if it's java 7. Else it returns a failure (non-zero). You can use ERRORLEVEL to check the return value and determine what the previous command returned.

Answer 2

打开cmd并检查JAVA_HOME点：

echo %JAVA_HOME%

Answer 3

if you want to detect installed java version, you should parse the result of "java -version". JAVA_HOME is only installation directory