网址的正则表达式模式，没有结尾斜杠，并排除网址中的某些文本

Question

I'm looking for preg_match_all pattern to find all URL on a page that don't have trailing slash.

For example: if I have

a href="/testing/abc/">end with slash

a href="/testing/test/mnl">no ending slash

The result would be #2. Solution is posted at find pattern for url with no ending slash

I have tried to modify the provided pattern to exclude urls that have 'images' or '.pdf' but no luck yet.

Thanks.

Answer 1

This one should suit your needs ( demo ):

href="(?:(?<!images).(?!(?:[.]pdf|/)"))*?"

• (?:) = non-capturing groupe
• (?<!images). = any char not preceded by images
• .(?!(?:[.]pdf|/)") = any char not followed by .pdf" nor by /"
• *? = match as short as possible

Answer 2

I found a way to exclude a link that has .pdf, by modifying the provided answer from the other question. Still looking at why it won't not match the images example though.

href=(['"])[^\s]+(?<![\/]|.pdf)\1

Link to a working test http://www.rubular.com/r/jmBVstpGZD