使用python查找单词的等级

Question

This is my program and it display the value if i give the complete name like if i type eng than it will show me only eng with value

import re
sent = "eng"
#sent=raw_input("Enter word")
#regex = re.compile('(^|\W)sent(?=(\W|$))')
for line in open("sir_try.txt").readlines():
    if sent == line.split()[0].strip():
        k = line.rsplit(',',1)[0].strip()
        print k
gene name        utr length
ensbta                  24
ensg1                   12
ensg24                  30
ensg37                  65
enscat                  22
ensm                    30

Actually what i want to do is that i want to search the highest value from the text file not through words , and it delete all the values from the text file of the same word having less value than the maximum like from the above text it should delete 12 , 30 for ensg , and than it should find the minimum value from the utr values and display it with name What you people answering me is , i already done it , and i mention it before my showing my program

Answer 1

Try instead of if sent == and replace it with a if sent in (line.split()[0].strip()):

That should check if the value of sent (engs) is anywhere in the argument (line.split()[0].strip()) in this case.

If you're still trying to only take the highest value, I would just create a variable value, then something along the lines of

if line.split()[1].strip() > value:
    value = line.split()[1].strip()

Test that out and let us know how it works for you.

Answer 2

please try this

file=open("sir_try.txt","r")
list_line=file.readlines()
file.close()
all_text=""

dic={}
sent="ensg"
temp_list=[]
for line in list_line:
    all_text=all_text+line
    name= line.rsplit()[0].strip()
    score=line.rsplit()[1].strip()
    dic[name]=score
for i in dic.keys():
    if sent in i:
        temp_list.append(dic[i])
hiegh_score=max(temp_list)

def check(index):
    reverse_text=all_text[index+1::-1]
    index2=reverse_text.find("\n")
    if sent==reverse_text[:index2+1][::-1][1:len(sent)+1]:
        return False
    else:
        return True

list_to_min=dic.values()
for i in temp_list:
    if i!=hiegh_score:
        index=all_text.find(str(i))
        while check(index):
            index=all_text.find(str(i),index+len(str(i)))
        all_text=all_text[0:index]+all_text[index+len(str(i)):]
        list_to_min.remove(str(i))
#write all text to "sir_try.txt"
file2=open("sir_try.txt","w")
file2.write(all_text)
file2.close()
min_score= min(list_to_min)
for j in dic.keys():
    if min_score==dic[j]:
        print "min score is :"+str(min_score)+" for person "+j

function check is for a bug in solotion for explain when your file is

gene name        utr length
ali                     12
ali87                   30
ensbta                  24
ensg1                   12
ensg24                  30
ensg37                  65
enscat                  22
ensm                    30

program delete ali score but we dont have it
by adding check function i solve it
and this version is final version answer

Answer 3

import operator
f = open('./sir_try.txt', 'r')
f = f.readlines()
del f[0]

gene = {}
matched_gene = {}

for line in f:
    words = line.strip().split(' ')
    words = [word for word in words if not word == '']
    gene[words[0]] = words[1]

# getting user input
user_input = raw_input('Enter gene name: ')
for gene_name, utr_length in gene.iteritems():
    if user_input in gene_name:
        matched_gene[gene_name] = utr_length
m = max(matched_gene.iteritems(), key=operator.itemgetter(1))[0]
print m, matched_gene[m]  # expected answer

# code to remove redundant gene names as per requirement

for key in matched_gene.keys():
    if not key == m:
        matched_gene.pop(key)
for key in gene.keys():
    if user_input in key:
        gene.pop(key)

final_gene = dict(gene.items() + matched_gene.items())
out = open('./output.txt', 'w')
out.write('gene name' + '\t\t' + 'utr length' + '\n\n')
for key, value in final_gene.iteritems():
    out.write(key + '\t\t\t\t' + value + '\n')
out.close()

Output:

Enter gene name: ensg
ensg37 65

Answer 4

To find out the name (first column) with the maximum value associated (second column), you need to first split the lines at the whitespace between name and value. Then you can find the maximum value using the built-in max() function. Let it take the value column as sorting criterion. You can then easily find out the corresponding name.

Example:

file_content = """
gene name        utr length
ensbta                  24
ensg1                   12
ensg24                  30
ensg37                  65
enscat                  22
ensm                    30
"""

# split lines at whitespace
l = [line.split() for line in file_content.splitlines()]

# skip headline and empty lines
l = [line for line in l if len(line) == 2]

print l

# find the maximum of second column
max_utr_length_tuple = max(l, key=lambda x:x[1])

print max_utr_length_tuple

print max_utr_length_tuple[0]

the output is:

$ python test.py
[['ensbta', '24'], ['ensg1', '12'], ['ensg24', '30'], ['ensg37', '65'], ['enscat', '22'], ['ensm', '30']]
['ensg37', '65'] 
ensg37

Answer 5

Short and sweet:

In [01]: t=file_content.split()[4:]
In [02]: b=((zip(t[0::2], t[1::2])))
In [03]: max(b, key=lambda x:x[1])
Out[03]: ('ensg37', '65')

Answer 6

Since you have tagged your question regex ,
Here's something that you would want to see and it's the only one (at the moment) that uses regex!

import re

sent = 'ensg' # your sequence
# regex that will "filter" the lines containing value of sent  
my_re = re.compile(r'(.*?%s.*?)\s+?(\d+)' % sent)

with open('stack.txt') as f:
    lines = f.read() # get data from file

filtered = my_re.findall(lines) # "filter" your data
print filtered

# get the desired (tuple with maximum "utr length")
max_tuple = max(filtered, key=lambda x: x[1]) 
print max_tuple

Output:

[('ensg1', '12'), ('ensg24', '30'), ('ensg37', '65')]
('ensg37', '65')