[英]Shell script issue with filenames containing spaces
I understand that one technique for dealing with spaces in filenames is to enclose the file name with single quotes: "'". 我知道处理文件名中空格的一种技术是用单引号将文件名引起来:“'”。
Why is it that the following code called, "echo.sh" works on a directory containing filenames with spaces, but the program "ls.sh" does Not work, where the only difference is 'echo' replaced with 'ls'? 为什么下面的代码“ echo.sh”在包含带空格的文件名的目录上起作用,但是程序“ ls.sh”却不起作用,唯一的区别是用“ ls”替换了“ echo”?
echo.sh 回声
#!/bin/sh
for f in *
do
echo "'$f'"
done
Produces : 产生 :
'abc' 'abc'
'def' 'def'
'echo.sh' 'echo.sh'
'ls.sh' 'ls.sh'
But, "ls.sh" fails: 但是,“ ls.sh”失败:
#!/bin/sh
for f in *
do
ls "'$f'"
done
Produces : 产生 :
ls: cannot access 'ab c': No such file or directory ls:无法访问“ ab c”:没有此类文件或目录
ls: cannot access 'de f': No such file or directory ls:无法访问“ de f”:没有此类文件或目录
ls: cannot access 'echo.sh': No such file or directory ls:无法访问“ echo.sh”:没有这样的文件或目录
ls: cannot access 'ls.sh': No such file or directory ls:无法访问“ ls.sh”:没有这样的文件或目录
you're actually adding redundant "'" (which your echo invocation shows) 您实际上是在添加多余的“'”(回声调用将显示该内容)
try this: 尝试这个:
#!/bin/sh
for f in *
do
ls "$f"
done
change the following line from 将以下行从
ls "'$f'"
into 进入
ls "$f"
Taking a closer look at the output of your echo.sh script you might notice the result is probably not quite the one you expected as every line printed is surrounded by '
characters like: 仔细观察echo.sh脚本的输出,您可能会注意到结果可能与预期的不太一样,因为打印的每一行都被
'
字符包围:
'file-1'
'file-2'
and so on. 等等。
Files with that names really don't exist on your system. 具有该名称的文件实际上在您的系统上不存在。 Using them with
ls
ls will try to look up a file named 'file-1'
instead of file-1
and a file with such a name just doesn't exist. 将它们与
ls
一起使用ls
将尝试查找名为'file-1'
而不是file-1
的文件,并且这样名称的文件不存在。
In your example you just added one pair of '
s too much. 在您的例子,你刚才添加1对
'
太过分了。 A single pair of double quotes "
is enough to take care of spaces that might contained in the file names: 一对双引号
"
足以处理文件名中可能包含的空格:
#!/bin/sh
for f in *
do
ls "$f"
done
Will work pretty fine even with file names containing spaces. 即使文件名包含空格,也可以正常工作。 The problem you are trying to avoid would only arise if you didn't use the double quotes around
$f
like this: 您试图避免的问题只会在您不使用
$f
这样的双引号的情况下出现:
#!/bin/sh
for f in *
do
ls $f # you might get into trouble here
done
What about this ? 那这个呢 ? =)
=)
#!/bin/sh
for f in *; do
printf -- '%s\n' "$f"
done
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