字母频率数组，将int转换为char

Question

My code below prints out a letter frequency table (number of letter occurances in a string) that is inputted from a scanner class. I Have everything working correctly except the last bit. When executed, the table displays letters az and the number of occurrences except for the last method LargestLength() method. Since my array 'score' uses int[26], instead of using az it uses ints 0-25. (0=A, 1=B, etc.) As of now my LargestLength method only displays the number (instead of the letter) which comes up the most but does not count the number of occurrences.

For example, If my string were to be "Hello", l shows up most frequently so i would like it to display, "Most Frequent: l 2" but with my code it displays "Most Frequent: 11" (11 = L). How would I go about fixing this?

Profile Class.

public class LetterProfile {
  int score[] = new int [26];

   public void countChars (String s) {
    s = s.toLowerCase();
    char a = 'a';
    for (int i = 0; i < s.length(); i++) {
      int next = (int)s.charAt(i) - (int) a;
      if ( next< 26 && next >= 0)
        score[next]++;

    }
 }

    public int largestLength() { 
      int largest = 0;
      int largestindex = 0;
      for(int a = 0; a<26; a++) {
        if(score[a] > largest) {
        largest = score[a];
        largestindex = a ;


      }
      }
      return (char) largestindex;
    }

    public void printResults() {
       largestLength();

       for (int i = 0; i < score.length; i++) {
    System.out.println( (char)(i+97) + ": " + score[i]);
       }
  System.out.println(("Most Frequent") + (": ") + largestLength());
    }
}

A bit of a confusing explanation but any help would be appreciated.

Answer 1

If my string were to be "Hello", l shows up most frequently so i would like it to display, "Most Frequent: l 2" but with my code it displays "Most Frequent: 11" (11 = L). How would I go about fixing this?

Simple: String.valueOf((char)(number + 'A'));