匹配无或多个Lua模式

Question

I am wondering if it was possible to make a pattern that could work like this:

With [icon=star w=32 h=32 spin=90] , it would return a table with:

icon: star  
w: 32  
h: 32  
spin: 90

I've tried doing [icon=(.-) ((.-)=(.-))] but it breaks.

Answer 1

Lua doesn't have regex in the literal sense. It uses patterns.

So, for your case, I'd much rather use gsub(or gmatch):

local str = "[icon=star w=32 h=32 spin=90]"
local tR = {}
str:gsub( "(%w+)%=(%w+)", function( x, y ) tR[x] = y end )

And your tR will have the exact result you wanted.

---

More tutorials on gmatch and gsub are:

• http://lua-users.org/wiki/StringLibraryTutorial
• http://www.lua.org/manual/5.1/manual.html#pdf-string.gmatch

Answer 2

Using the following expression: (\\w+(?=\\=))=((?<=\\=)\\w+) group 1 of each match would be the left hand side and group 2 of each match would be the right hand side.

Example: http://regexr.com?3478b

Answer 3

Try this:

(\w+)=(\w+)

Each match will have two groups:

• Group 1 will be the "name"
• Group 2 will be the "value"

Answer 4

for k, v in ("[icon=star w=32 h=32 spin=90]"):gmatch("(%w+)=(%w+)")
  do print(k..":",v) end

icon:   star
w:  32
h:  32
spin:   90