PyQt多个QDilaog类信号捕获

Question

I have a PyQt Gui application that has multiple QDialog windows that I use to plot data using matplotlib widget. This is the code I'm using is below.

Only one emitted signal is caught. Which ever QDialog is created last catches it's emitted signal. If the TempBox dialog is created last the NewTemp_signal is caught, or if the RealBox dialog is created last the NewReal_signal is caught. But, the other signal is not caught. How do I catch both signals to update all dialogs? Thanks

Dialog window class

class GUIgraph(QtGui.QDialog):
    def __init__(self,parent=None):
       QtGui.QDialog.__init__(self,parent)
       print 'This is the Histograph dialog class function'
       self.graph = Ui_histogram_Dialog()
       self.graph.setupUi(self)

Functions that create new windwos

def TempgraphFunc(self):
    QtGui.QWidget.__init__(self,parent=None)
    self.TempBox = GUIgraph()
    self.TempBox.setWindowTitle("Temperature")
    self.NewTemp_signal.connect(self.TempPlotFunc)
    self.TempBox.show()

def RealgraphFunc(self):
    QtGui.QWidget.__init__(self,parent=None)
    self.RealBox = GUIgraph()
    self.RealBox.setWindowTitle("Real Space")
    self.NewReal_signal.connect(self.RealPlotFunc)
    print 'Real is connected'
    self.RealBox.show()

In another function I emit a signal

def loadFiles(self):
    ....
    self.NewTemp_signal.emit()
    self.NewReal_signal.emit()
    print ' signals emitted' 

Answer 1

I think you have architectural problems. I don't see all your code, but at least this is very strange:

def TempgraphFunc(self):
    QtGui.QWidget.__init__(self,parent=None)
    self.TempBox = GUIgraph()
    self.TempBox.setWindowTitle("Temperature")
    self.NewTemp_signal.connect(self.TempPlotFunc)
    self.TempBox.show()

In a method you are calling QtGui.QWidget.__init__ ??? __init__ is the parent 'constructor' method, and you are supposed to call it from a subclass overridden __init__