JavaScript正则表达式查找第一个不等于

Question

I have, what I thought was, a simple regex to get anything not (letter), (number) or (%)

str.indexOf(/[^a-zA-Z0-9%]/);

However, I'm ALWAYS getting -1 .

Here's an example str :

Check out this awesome video!

What am I doing wrong?

Answer 1

You cannot put regex into indexOf. Use search instead.

See this for more info: Is there a version of JavaScript's String.indexOf() that allows for regular expressions?

Answer 2

"Check out this awesome video!".replace(/./g,function(match){
  return '0x'+match.charCodeAt(0).toString(16);
});

returns the hexadecimal representation of the string. If you want just convert alpha-numeric characters, replace the . in the regex by \\w .