Bash脚本将带空格分隔标记的字符串转换为数组

Question

I have a string

echo $STRING

which gives

first second third fourth fifth

basically a list separated spaces.

how do i take that string and make it an array so that

array[0] = first
array[1] = second

etc..

I have tried

IFS=' ' read -a list <<< $STRING

but then when i do an

echo ${list[@]}

it only prints out "first" and nothing else

Answer 1

It's simple actually:

list=( $STRING )

Or more verbosely:

declare -a list=( $STRING )

PS: You can't export IFS and use the new value in the same command. You have to declare it first, then use it's effects in the following command:

$ list=( first second third )
$ IFS=":" echo "${list[*]}"
first second third
$ IFS=":" ; echo "${list[*]}"
first:second:third