jdb打印捕获到异常消息

Question

I have exceptions thrown in my java code when an error occurs. I then run the code using jdb so when the exception occurs, I can see the state that the code is in and debug. For all exceptions that I throw, I put in a useful string message. However, when jdb catches the exception, it doesn't print this string along with it. How do I print this string?

I have googled and searched and read the documentation but I can't figure out how.

If I have the test class:

public class Test{
    public static void main(String[] args){
        throw new IllegalArgumentException("How do I view this string through jdb?");
    }
}

And run it through jdb:

$ jdb Test
Initializing jdb ...
> run
run Test
Set uncaught java.lang.Throwable
Set deferred uncaught java.lang.Throwable
> 
VM Started: 
Exception occurred: java.lang.IllegalArgumentException (uncaught)"thread=main", Test.main(), line=3 bci=9

main[1] 

Answer 1

Check out the JDB "catch" command, for example "catch IllegalArgumentException". Per the JDB docs , it will cause the debugger to break when the exception is thrown so that you can probe into the details. This document on debugging does a nice job explaining some of the downsides to being dependant on "print" statements, and also references the JDB "catch" functionality.