Python：从用户输入中打印常用字母

Question

Is there a better way the write this code. While there are no errors it seems that its printing all the letters I typed sorted into a list.

I want to print the common letters in a string, even if more than one.

Here is what I Have

mystr = input("Enter a string:")
s = list(mystr) 
letter_counter = {}
for word in mystr:
    if word in letter_counter:
         letter_counter[word] += 1
    else:
         letter_counter[word] = 1

 user_letter = sorted(letter_counter, key = letter_counter.get, reverse = True)

 number_1 = user_letter[:2]
 print(number_1)  

The only way I can print the correct letters is by setting a limit on

number_1 = user_letter[:2]

For example if I enter the following:

mystr = input("Thomas Jones")

in the code the printed output would be

print(number_1)       
[o], [s]

Which is right but if the limit was set to from 2 to 3

number_1 = user_letter[:3]

It will print [o] [s] [a] there is only one a it shouldn't be there. I want it so that any amount the of words the user inputs it will show the correct repeated letter without the limiter.

I'm liberality stuck I have no idea how to correct this

Answer 1

from collections import Counter
[letter for letter,count in Counter("Thomas Jones").items() if count > 1]

Answer 2

Your code produces

letter_counter = {'a': 1, ' ': 1, 'e': 1, 'h': 1, 'J': 1, 'm': 1, 'o': 2, 'n': 1, 's': 2, 'T': 1}
user_letter = ['o', 's', 'a', ' ', 'e', 'h', 'J', 'm', 'n', 'T']

which is all correct.

If you only want the repetitive letters, try

user_letter = [letter for letter in letter_counter if letter_counter[letter] > 1]

or something similar.