[英]Floating Point Exception when dividing in x86 nasm
I'm busy with learning Assembly and was looking at dividing, however I ran into a pickle with the following statement: 我正忙着学习装配,正在考虑分裂,但是我遇到了以下声明:
mov edx,0x00000001
mov eax,0x00000000
mov ecx,0x00000002
idiv ecx
GDB: GDB:
0x08048071 <+17>: mov edx,0x1
0x08048076 <+22>: mov eax,0x0
0x0804807b <+27>: mov ecx,0x2
=> 0x08048080 <+32>: idiv ecx
I wanted to divide 0x100000000 by 0x00000002, so since the span for division is EDX:EAX I moved 0x1 into EDX and 0x0 into EAX. 我想将0x100000000除以0x00000002,因为除法的范围是EDX:EAX我将0x1移动到EDX,将0x0移动到EAX。 I then move 0x2 into ECX and divide, this unfortunately gives me a floating point exception, I' m not sure what I did wrong.
然后我将0x2移动到ECX并进行除法,这不幸地给了我一个浮点异常,我不确定我做错了什么。
When using div (unsigned) it works normal, so I wonder what the difference is in interpretation between div and idiv for this particular statement which causes the exception. 当使用div(无符号)时它工作正常,所以我想知道这个导致异常的特定语句在div和idiv之间的解释有什么不同。
The quotient ( 0x80000000
) doesn't fit into a 32-bit signed integer (max value: 0x7fffffff
). 商(
0x80000000
)不适合32位有符号整数(最大值: 0x7fffffff
)。 Hence you get an exception. 因此你得到一个例外。 It does fit into a 32-bit unsigned integer (max value
0xffffffff
), so no exception is triggered by an unsigned divide. 它确实适合32位无符号整数(最大值
0xffffffff
),因此无符号除法不会触发异常。
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