如何在Python中使用“由HTML编写的” URL解析HTML代码？

Question

I am starting to program in Python, and have been reading a couple of posts where they say that I should use an HTML parser to get an URL from a text rather than re.

I have the source code which I got from page.read() with the urllib and urlopen .

Now, my problem is that the parser is removing the url part from the text.

Also, if I had read correctly, var = page.read() , var is stored as a string?

How can I tell it to give me the text between 2 "tags"? The URL is always in between flv= and ; so and as such it doesn't start with href which is what the parsers look for, and it doesn't contain http:// either.

I have read many posts, but it seems they all look for ``href in the code.

Do I have it all completely wrong?

Thank you!

Answer 1

You could consider implementing your own search / grab. In psuedocode, it would look a little like this:

find location of 'flv=' in HTML = location_start
find location of ';' in HTML = location_end
grab everything in between:   HTML[location_start : location_end]

You should be able to implement this in python.

Good luck!