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类型NoneType的对象没有len

[英]object of type NoneType has no len

def medianeven (L):
    while len(L) > 2:
        L = L[1:(len(L)-1)]
    return average (L)

def medianodd (L):
    while len(L) > 1:
        L = L[1:(len(L)-1)]
    return L[0]

def median (L):
    new = L.sort()
    a = len(new)
    if a % 2 == 0:
        medianeven(new)
    else:
        medianodd(new)

It says TypeError: object of type 'NoneType' has no len() . 它说TypeError: object of type 'NoneType' has no len() Both medianeven and medianodd work, but median itself is not functioning. median medianevenmedian medianodd起作用,但是median本身不起作用。

.sort() is in-place and returns None . .sort()就位并返回None

Change this line: 更改此行:

new = L.sort()

To just this: 为此:

L.sort()

And replace all of your instances of new with just L . 并仅用L替换所有new实例。 You also need to return the results of those function calls: 您还需要return这些函数调用的结果:

if a % 2 == 0:
    return medianeven(new)
else:
    return medianodd(new)

Also, Python's slices support negative indices, so this code: 另外,Python的切片支持负索引,因此此代码:

L[1:(len(L)-1)]

Can be simplified to just 可以简化为

L[1:-1]

The sort() method call you have in the line: 您在该行中进行的sort()方法调用:

new = L.sort();

doesn't return anything. 不返回任何东西。 Thus 'new' holds 'None', which has no length. 因此,“新”持有“无”,没有长度。 I believe doing L.sort() will sort the list in place. 我相信这样做L.sort()可以对列表进行排序。 Don't need to store it in 'new'. 不需要将其存储在“ new”中。

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