想要用等效的UTF-8符号替换特殊字符

Question

As part of my application I have written a custom method to extract data from the DB and return it as a string. My string has special characters like the pound sign, which when extracted looks like this:

"MyMobile Blue £54.99 [12 month term]"

I want the £ to be replaced with actual pound symbol. Below is my method:

public String getOfferName(String offerId) {
    log(Level.DEBUG, "Entered getSupOfferName");
    OfferClient client = (OfferClient) ApplicationContext
            .get(OfferClient.class);
    OfferObject offerElement = getOfferElement(client, offerId);
    if (offerElement == null) {
        return "";
    } else {

        return offerElement.getDisplayValue();
    }
}

Can some one help on this?

Answer 1

The document contains XML/HTML entities .

You can use the StringEscapeUtils.unescapeXml() method from commons-lang to parse these back to their unicode equivalents.

If this is HTML rather than XML use the other methods as there are differences in the two sets of entities.

Answer 2

I voted for StringEscapeUtils.unescapeXml() solution. Anyway, here's is a custom solution

    String s = "MyMobile Blue £54.99 [12 month term]";
    Pattern p = Pattern.compile("&#(\\d+?);");
    Matcher m = p.matcher(s);
    StringBuffer sb = new StringBuffer();
    while(m.find()) {
        int c = Integer.parseInt(m.group(1));
        m.appendReplacement(sb, "" + (char)c);
    }
    m.appendTail(sb);
    System.out.println(sb);

output

MyMobile Blue £54.99 [12 month term]

note that it does not accept hex entity reference