[英]jquery toggle function open/close
Trying to do a function that does "A" when toggle open and "B" when toggle close. 尝试执行一个功能,当扳机打开时执行“ A”,当扳机关闭时执行“ B”。
Code: 码:
function awesome_toggle()
{
$(".button").click(function()
{
$("content").toggle(
function()
{
/* Do "A" */
},
function()
{
/* Do "B" */
}
);
});
}
This code doesn't seem to work and I can't figure out why. 这段代码似乎无效,我也不知道为什么。 When I use only one function, so I stop the code after /* Do "A" */ it works but when I add the /* Do "B" */ function it stops working.
当我仅使用一个函数时,因此我在/ * Do“ A” * /之后停止了代码,但是在我添加/ * Do“ B” * /函数之后,它停止了工作。 What is wrong?
怎么了?
jquery version: ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js jQuery版本:ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js
As the comments have said, this version of toggle
has been deprecated. 正如评论所说,此版本的
toggle
已被弃用。
There may very well be a better way to accomplish what you want, but you can check whether the element is visible after toggle with the :visible
selector, and do stuff conditionally based upon that. 可能有更好的方法来完成所需的操作,但是您可以使用
:visible
选择器切换后检查元素是否可见,并根据该条件有条件地进行处理。
function awesome_toggle()
{
$(".button").click(function() {
$("content").toggle(normalSpeed, function () {
if ($("content").is(':visible')) {
/* Do "A" */
} else {
/* Do "B" */
}
});
});
}
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