如何使用django @lazy decorator？

Question

First try with the django.utils.functional.lazy decorator. My function returns two lists, so I'm decorating it with @lazy(list, list). It's a plain jane function, not a method/property on a class.

I'm getting a "' proxy ' object is not callable" when I try to call the resulting decorated function.

Answer 1

I don't think you can use Django's lazy as decorator. You can use it as a function call:

lazy_function = lazy(f, type)

where f is the function you need to make lazy and type is the expected data type.

Also how do you return the two lists? Like:

def a():
    return [], []

If yes, then technically you are returning a tuple hence you should use lazy as:

lazy_f = lazy(f, tuple)