如何在AjaxFileUpload onuploadComplete事件中获取选定的dropdownvalue？

Question

      <%@ Page Language="C#" AutoEventWireup="true" CodeFile="test.aspx.cs"  Inherits="test"%>

      <%@ Register assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" tagprefix="asp" %>

       <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

      <html xmlns="http://www.w3.org/1999/xhtml">
       <head runat="server">
       <title></title>
      </head>
      <body style="height: 162px">
<form id="form1" runat="server">
<div>

    <asp:RadioButton ID="MCA" runat="server" Text="MCA" AutoPostBack="True" 
        oncheckedchanged="MCA_CheckedChanged" />
    <br />

</div>
<asp:DropDownList ID="DropDownList1" runat="server" AutoPostBack="True">
    <asp:ListItem Value="Sem1"></asp:ListItem>
    <asp:ListItem Value="Sem2"></asp:ListItem>
</asp:DropDownList>
<br />
<asp:DropDownList ID="DropDownList2" runat="server" AutoPostBack="True" 
    onselectedindexchanged="DropDownList2_SelectedIndexChanged" 
    ViewStateMode="Enabled">
    <asp:ListItem Value="MCA101"></asp:ListItem>
    <asp:ListItem Value="MCA103">MCA103</asp:ListItem>
</asp:DropDownList>
<br />
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
<br />

<asp:UpdatePanel ID="UpdatePanel1" runat="server">
    <ContentTemplate>
     <br />
        <asp:AjaxFileUpload ID="AjaxFileUpload1" runat="server" 
            OnUploadComplete="upload"/>
    <br />
    </ContentTemplate>
</asp:UpdatePanel>
</form>
</body>
</html>

Event Code.. 事件代码

      protected void upload(Object sender, AjaxControlToolkit.AjaxFileUploadEventArgs e)
      {
        string s = DropDownList1.SelectedValue;
        string t = DropDownList2.SelectedValue;
        string path= string path = Server.MapPath("~/MCA/" + s + "/" +t+ "/")+e.FileName 
      }

//Both s and t get the first value of Dropdownlist even if some other value selected and that's uploading is not done as per directort structure. // s和t都将获得Dropdownlist的第一个值，即使未选择其他某些值且该上载未按照目录结构完成。

Both Dropdownlist have several values and postback property is true for both the list. 两个Dropdownlist都有多个值，并且两个列表的postback属性均为true。

How to get the exact selected value of list ? 如何获得列表的确切选择值？

Answer 1

Issue is Request.Form["__VIEWSTATE"] = null when AjaxFileUpload OnUploadComplete event is called. 当调用AjaxFileUpload OnUploadComplete事件时，问题是Request.Form["__VIEWSTATE"] = null 。

Fix for this issue (C# Code): 解决此问题的方法 （C＃代码）：

Set dropdown selection in session at page load. 在页面加载时在会话中设置下拉选择。

protected void Page_Load(object sender, EventArgs e)
{
 if (Request.Form["__VIEWSTATE"] != null)
    Session["Path"] = "//" + DropDownList1.SelectedValue + "//" + DropDownList2.SelectedValue + "//";
}

Use session value for the creation of filepath: 使用会话值创建文件路径：

protected void upload(Object sender, AjaxControlToolkit.AjaxFileUploadEventArgs e)
{
        string path = string.Empty;
        if (Session["Path"] != null)
            path = Server.MapPath("~//MCA" + (string)Session["Path"]) + e.FileName;
}

Answer 2

我相信您需要将下拉列表添加到与上传控件相同的更新面板中。

如何在AjaxFileUpload onuploadComplete事件中获取选定的dropdownvalue？

问题描述

2 个解决方案

解决方案1
0 2013-03-26 10:52:03

解决方案2
0 2013-03-26 13:16:10

如何在AjaxFileUpload onuploadComplete事件中获取选定的dropdownvalue？

问题描述

2 个解决方案

解决方案1 0 2013-03-26 10:52:03

解决方案2 0 2013-03-26 13:16:10

解决方案1
0 2013-03-26 10:52:03

解决方案2
0 2013-03-26 13:16:10