简体   繁体   English

从具有Lambda表达式的Lambda表达式中选择

[英]Selecting from Lambda Expression with Lambda Expression

I have two expressions: 我有两个表达:

  public static Expression<Func<TSource, TReturn>> Merge<TSource, TSource2, TReturn>(
      Expression<Func<TSource, TSource2>> foo1
      Expression<Func<TSource2, TReturn>> foo2)
  {
      // What to do?
  }

How can I merge them into a single expression, so the output from the first is used as the input for the second? 如何将它们合并为一个表达式,以便将第一个的输出用作第二个的输入? I am new to these and so far its just been exceptions. 我是新手,到目前为止,只是个例外。

Thanks 谢谢

This depends a lot on which providers need to use it. 这在很大程度上取决于哪些提供商需要使用它。 Some will be fine with: 有些可以使用:

public static Expression<Func<TSource, TReturn>>
     Merge<TSource, TSource2, TReturn>(
  Expression<Func<TSource, TSource2>> foo1,
  Expression<Func<TSource2, TReturn>> foo2)
{
    return Expression.Lambda<Func<TSource, TReturn>>(
      Expression.Invoke(foo2, foo1.Body),
      foo1.Parameters);
}

However, others (EF) will not. 但是,其他人(EF)不会。 You can also re-write the expression-tree with a visitor to inline the expression: 您还可以用访问者重写表达式树以内联表达式:

public static Expression<Func<TSource, TReturn>>
      Merge<TSource, TSource2, TReturn>(
  Expression<Func<TSource, TSource2>> foo1,
  Expression<Func<TSource2, TReturn>> foo2)
{
    var swapped = new SwapVisitor(
        foo2.Parameters.Single(), foo1.Body).Visit(foo2.Body);
    return Expression.Lambda<Func<TSource, TReturn>>(
        swapped, foo1.Parameters);
}

class SwapVisitor : ExpressionVisitor
{
    private readonly Expression from, to;
    public SwapVisitor(Expression from, Expression to)
    {
        this.from = from;
        this.to = to;
    }
    public override Expression Visit(Expression node)
    {
        return node == from ? to : base.Visit(node);
    }
}

this will work with all providers. 这将适用于所有提供商。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM