[英]Why does Matlab gives different value than C++
I am creating a huge program in c++ for computer vision, and for debugging purposes I use Matlab. 我正在用c ++创建一个用于计算机视觉的大型程序,并且出于调试目的,我使用Matlab。 After time fighting with it I realised that some simple arithmetic equation's answer is different when using Matlab and c++ (Visual studio 9 compiler BTW). 经过一段时间的努力,我意识到使用Matlab和c ++(Visual Studio 9编译器BTW)时一些简单的算术方程的答案是不同的。 why is that? 这是为什么?
Here is the arithmetic operation: 这是算术运算:
Matlab function: Matlab功能:
function [x,y]=shape_fun(p,shape,Ax,Ay)
x=p(1)+Ax+shape(1)+Ax.*shape(3)+Ay.*shape(4)+Ax.*Ax.*shape(5)/2+Ay.*Ay.*shape(6)/2+Ax.*Ay.*shape(7);
y=p(2)+Ay+shape(2)+Ax.*shape(8)+Ay.*shape(9)+Ax.*Ax.*shape(10)/2+Ay.*Ay.*shape(11)/2+Ax.*Ay.*shape(12);
end
C++ function C ++函数
cv::Point2d deformed(const double shape_fun[12],const cv::Point2d p,const double Ax,const double Ay){
cv::Point2d result;
result.x=(p.x+Ax)+shape_fun[0]+shape_fun[2]*Ax+shape_fun[3]*Ay+shape_fun[4]*Ax*Ax/2*shape_fun[5]*Ay*Ay/2+shape_fun[6]*Ax*Ay;
result.y=(p.y+Ay)+shape_fun[1]+shape_fun[7]*Ax+shape_fun[8]*Ay+shape_fun[9]*Ax*Ax/2*shape_fun[10]*Ay*Ay/2+shape_fun[11]*Ax*Ay;
return result;
}
Data: 数据:
Note: Matlab values are copy-pasted from debbuger c++ values, they are EXACTLY the same. 注意:Matlab值是从debbuger c ++值复制粘贴而成的,它们完全相同。
Ax=-12
Ay=-12
p=[468,683];
shape=[
63.178114688537441
36.536135487588474
-0.038695673779030673
-0.045313362559036965
0.016469896824803026
0.0017122284868442948
-0.0030285669997117204
-0.067902655024060773
0.17995980761526389
0.012716871878336870
-0.036890386929202310
-0.00081243692842574420
];
results: 结果:
Matlab : Matlab的 :
x =
3.947029931219995e+02
y =
7.043339656551383e+02
C++: C ++:
result {x=393.54007007383439 y=703.64248713855773 } cv::Point_<double>
Note: I am not tagging the question as OpenCV
on purpose. 注意:我不是故意将问题标记为OpenCV
。 While evidently I am using OpenCV
in C++, cv::Point2d
is just a struct with two double
variables, x and y, and I don't think this question is about OpenCV
at all. 虽然显然我在C ++中使用OpenCV
,但cv::Point2d
只是具有两个double
变量x和y的结构,我根本不认为这个问题与OpenCV
有关。
result.x=
(p.x+Ax)+
shape_fun[0]+
shape_fun[2]*Ax+
shape_fun[3]*Ay+
shape_fun[4]*Ax*Ax/2*
shape_fun[5]*Ay*Ay/2+
shape_fun[6]*Ax*Ay;
result.y=
(p.y+Ay)+
shape_fun[1]+
shape_fun[7]*Ax+
shape_fun[8]*Ay+
shape_fun[9]*Ax*Ax/2*
shape_fun[10]*Ay*Ay/2+
shape_fun[11]*Ax*Ay;
should be (presumably) 应该(大概)
result.x=
(p.x+Ax)+
shape_fun[0]+
shape_fun[2]*Ax+
shape_fun[3]*Ay+
shape_fun[4]*Ax*Ax/2+ /** change here **/
shape_fun[5]*Ay*Ay/2+
shape_fun[6]*Ax*Ay;
result.y=
(p.y+Ay)+
shape_fun[1]+
shape_fun[7]*Ax+
shape_fun[8]*Ay+
shape_fun[9]*Ax*Ax/2+ /** change here **/
shape_fun[10]*Ay*Ay/2+
shape_fun[11]*Ax*Ay;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.