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根据多个文件输入检查现有文件名

[英]checking exisiting filenames against muliple file input

I have a file verification process which checks if a filename is already in the database by making an ajax call. 我有一个文件验证过程,该过程通过进行ajax调用来检查数据库中是否已存在文件名。 This works if there is only 1 filename echoed in existing-filenames.php, but I can't figure out how I can loop through the return data to check every filename in the multiple file input against every result from the existing-filenames.php loop. 如果existing-filenames.php中仅回显了1个文件名,则此方法有效,但是我无法弄清楚如何遍历返回数据,以对照现有文件名.php的每个结果检查多文件输入中的每个文件名环。 any advice much appreciated. 任何建议,不胜感激。 thanks 谢谢

var file = $('#file')[0];
$.get('existing-filenames.php', function(data){

  for (var i=0; i<file.files.length; i++) {
       var fname = file.files[i].name;

        if(fname == data){ 
          alert("these files already exist:" + data); 
          return false;
        }
      }
  });

and in 'existing-filenames.php' 和在“ existing-filenames.php”中

$allfiles = $db->query("SELECT filename FROM files WHERE email = '$_SESSION[email]'");

    while($result = $allfiles ->fetch_assoc()) {
    echo $result['filename'];
}

In your PHP file you're just printing all file paths without a space or a new line. 在您的PHP文件中,您仅打印所有文件路径,而无需空格或换行。 Also you should use prepared statements for your query, include $_SESSION['email'] without any check is not safe at all. 另外,您应该对查询使用准备好的语句,包括$_SESSION['email']而不进行任何检查根本不安全。

By the way, try edit your PHP file like this: 顺便说一句,尝试像这样编辑您的PHP文件:

$allfiles = $db->query("SELECT filename FROM files WHERE email = '$_SESSION[email]'");

$fileList = array();
while($result = $allfiles ->fetch_assoc()) {
    $fileList[] = $result['filename'];
}

echo json_encode($fileList);

And your JS code like this: 和你的JS代码是这样的:

$.get('existing-filenames.php', function(data){
      for (var i=0; i<file.files.length; i++) {
       var fname = file.files[i].name;

        if(data.indexOf(fname) >= 0){ 
          alert("these files already exist:" + data); 
          return false;
        }
      }
  }, 'json');

Not tested, but it should work 未经测试,但应该可以工作

Try changing your JS to: 尝试将您的JS更改为:

var file = $('#file')[0];
$.getJSON('existing-filenames.php', function(data){

  for (var i=0; i<file.files.length; i++) {
     var fname = file.files[i].name;

      if(~data.indexOf(fname)){ 
        alert("these files already exist:" + data); 
        return false;
      }
  }
});

And in your PHP file: 在您的PHP文件中:

$result = [];
while( $files = $allfiles ->fetch_assoc() ){
    $result[] = $files['filename'];
}
echo json_encode($result);

... I think. ... 我认为。 I hardly ever write PHP. 我几乎从未写过PHP。

var fileNames = $('.file-name').text();

fileNames.forEach(function(fileName){
     $.get('url',{filename: fileName},function(data){
                  ....
       });
 });

My approach would be getting the filenames into an array and making the get request with different parameters each time 我的方法是将文件名放入数组中,并每次使用不同的参数发出get请求

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