简体   繁体   English

mysql-在逗号分隔的文本字段中找到匹配项

[英]mysql - find match in comma seperated text field

I am having problems with output from my (MySQL) database. 我的(MySQL)数据库输出出现问题。

attractionData database 吸引力数据数据库

 id |  tags
-------------------------------------

 1  |  castle a, castle b, fakecastle c
 2  |  museum a, fakemuseum b, museum c
 ...

And on a site I have an input field, which has autoSuggest function. 在站点上,我有一个输入字段,该字段具有autoSuggest功能。 So in my jQuery I have an .keyup event, which send data to ajax file, and the ajax file outputs the list of suggestions (autosuggest). 因此,在我的jQuery中,我有一个.keyup事件,该事件将数据发送到ajax文件,而ajax文件输出建议列表(自动建议)。

So now if I type in the input "castle a..." it will output the "1" (im outputting the id). 因此,现在如果我输入输入“ castle a ...”,它将输出“ 1”(即输出id)。 And if i type in "museum a" it will return "2". 如果我输入“博物馆a”,它将返回“ 2”。

So my question is... Is it somehow possible that if I would type in "fakecastle" that it would return "1"? 所以我的问题是...如果我键入“ fakecastle”,是否有可能返回“ 1”? I know this could be done with the explode(',', $string) . 我知道这可以通过explode(',', $string)

I've been messing around with FIND_IN_SET(), but I somehow didn't achieve the result I wanted. 我一直在搞弄FIND_IN_SET(),但是我不知何故没有达到我想要的结果。 So I am still stucked with 所以我仍然坚持

mysql_query("SELECT tags FROM attractionData WHERE (tags LIKE '$search%') ") $search = text from the input field. mysql_query("SELECT tags FROM attractionData WHERE (tags LIKE '$search%') ") $ search =来自输入字段的文本。

EDIT 编辑

if(isset($_POST['search']) == true && empty($_POST['search']) == false){
    $search = $_POST['search'];
    $search = mysql_real_escape_string($search);

    $query = mysql_query("SELECT tags FROM attractionData WHERE (tags LIKE '$search%') ")
    while(($row = mysql_fetch_assoc($query)) !== false){
        echo "<li class='auto'>".$row['friendEmail'] ."</li>";
}

Any help would be appreciated 任何帮助,将不胜感激

Ty, Sebastian Ty,塞巴斯蒂安

在此处此处此处阅读有关数据库规范化的信息 ,如果您遵循规范化的步骤,那么在此期间可能会自动解决这些问题,并且您的数据库会更有用。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM