Linux-查找字符串并获得下一部分

Question

If I have a string like "name":"tempname","department":"tempdept", I want to search for the value for "department" which is "tempdept". So if "department" exists, I need just the value returned. The length of the string that is searched can be very long. Is this possible using sed/awk, can you please help?

I tried the following, but it returns the whole string. I am searching for department here.

echo $data | sed 's/\(\"department\":\)\(.*\"\)/\2/'

Answer 1

Some simple solutions:

echo "$data" | tr , \\n | awk -F: '$1 ~ /^department$/{ print $2 }'

or

echo "$data" | awk -F: '$1 ~ /^department$/{ print $2 }' RS=,

Your solution just need minor modifications:

echo "$data" | tr , \\n | sed -n 's/"department":\(.*\)/\2/p'

or

echo "$data" | tr , \\n | sed -n '/"department":/s///p'

Answer 2

See if this does it for you:

sed -ne '/"department"/{s/^.*"department":"\([^"]*\).*/\1/;p;}'

Example:

echo '"name":"tempname","department":"tempdept"' | sed -ne '/"department"/{s/^.*"department":"\([^"]*\).*/\1/;p;}'
tempdept

If you need to retain the double quotes, just add them back in during the replacement:

    sed -ne '/"department"/{s/^.*"department":"\([^"]*\).*/"\1"/;p;}