Nokogiri用xpath解析XML

Question

Im trying to figure out how to parse returned XMl via an api call, Im using Nokogiri and am trying to use xpath. What i would like to do is display all "title" attributes that have been returned

So far i have in a method

def getcontact
doc = Nokogiri::XML(open(url))
doc.xpath('//xmlns:feed/xmlns:entry')
end

controller

@mycontacts = getcontact

View

<% @mycontacts.each do |c| %>
 <%= c.xpath("//title") %>
<% end %>

The XML

<entry>
 <id>xxx</id>
 <updated>xxx</updated> 
 <category  scheme="xxx"  term="xxx"/>
 <title type="text">xxx</title>
 <link rel="xxx" type="xxx"    href="xxx"/> 
 <link rel="xxx0gmail.com/b6ea0e8ddbc4e5"/>     
 <link rel="xx" type="xxx" href="xxx"/> <link rel="xx" type="axx" href="xxx"/> 
 <gd:email rel="xxx" address="xxx" primary="xx"/> 
</entry>

i am getting nothing returned, could someone point out what i am doing wrong please, also i notice there is html tags in the returned XML, can i strip this out, for example type=text is within the title attribute

Update

So i have tried this

doc.xpath('//xmlns:feed/xmlns:entry/xmlns:title').text

but this returns all the titles as a string

Update 2

View

<% @mycontacts.each do |c| %>
 <%= c.xpath('xmlns:title').text %><br>
<% end %>

method

doc.xpath('//xmlns:feed/xmlns:entry')

so this lists all my titles but if there are any blank entries there is an empty record. Need to remove these from the loop now i guess

Is this correct, is there a better way to do it?

Thanks

Answer 1

With method 2, try using:

d.xpath('//feed/entry[title[node()]]'

This will return a nodeset containing nodes that have a non-empty title. Then you can iterate over set however you like.