[英]PHP: check row exist using mysqli query
i have this two function for create user.first function for insert/create user and other function for check if user was/exist in MySql
database. 我有这两个功能来创建用户。第一个功能用于插入/创建用户和其他功能用于检查用户是否存在于
MySql
数据库中。 but when i send data i see blank page for die(); 但是当我发送数据时,我看到die()的空白页; (if user exsit or user not exist) how to fix this error?
(如果用户已存在或用户不存在)如何解决此错误? and how to print error list in red box ie:
以及如何在红色框中打印错误列表,即:
- this user not activate
- email is empty
- ....
my class: 我的课:
public function createUser($email, $password, $salt, $verification) {
if($this->checkUserFound($email) != true ){die();}
$query = "INSERT INTO tbUsers (email, password, user_salt, is_verified, is_active, is_admin, verification_code) "
. "VALUES (?, ?, ?, ?, ?, ?, ?)";
$stmt = $this->_db->prepare($query);
$ver = 0;
$act = 1;
$adm = 0;
$stmt->bind_param("sssiiis", $email, $password, $salt, $ver, $act, $adm, $verification);
if ($stmt->execute()) {
return true;
}
return false;
}
public function checkUserFound($email) {
$query = "SELECT email FROM tbUsers where email = ?";
$stmt = $this->_db->prepare($query);
$stmt->bind_param("s", $email);
if ($stmt->execute()) {
$stmt->bind_result($email);
//fetch first row of results
$stmt->fetch();
return false;
}
return true;
}
This is always going to return FALSE
(assuming the query successfully executes): 这总是返回
FALSE
(假设查询成功执行):
if ($stmt->execute()) {
$stmt->bind_result($email);
//fetch first row of results
$stmt->fetch();
return false;
}
You want to change it to: 您想要将其更改为:
if ($stmt->execute()) {
$stmt->store_result();
return 0 == $stmt->num_rows ? FALSE : TRUE;
}
Then, if the user is found, it will return TRUE
; 然后,如果找到该用户,它将返回
TRUE
; if not if will return FALSE
. 如果不是,则返回
FALSE
。
Also, I think it make more sense (semantically) to have this: 另外,我认为(从语义上)具有以下含义更有意义:
if($this->checkUserFound($email)){die();}
... because you want it to return TRUE
if the user is found (and end the script because you don't want to insert a duplicate)./ ...,因为您希望它在找到用户后返回
TRUE
(并结束脚本是因为您不想插入重复项)。/
if ($stmt->execute()) {
$stmt->bind_result($email);
//fetch first row of results
$stmt->fetch();
return true;
}
return false;
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