MySQL-如何获取重复项的相邻字段之和

Question

I want to get the total points for each pizza. So, for example, Caramelized Onion should have 12 points, and Breakfast should have five.

SQLFIDDLE link here. Here is the MySQL query:

SELECT pizza_table.name, results_table.first_pick_points as points
FROM results_table, pizza_table
WHERE results_table.first_pick = pizza_table.id
UNION
SELECT pizza_table.name, results_table.second_pick_points
FROM results_table, pizza_table
WHERE results_table.second_pick = pizza_table.id
UNION
SELECT pizza_table.name, results_table.third_pick_points
FROM results_table, pizza_table
WHERE results_table.third_pick = pizza_table.id
UNION
SELECT pizza_table.name, results_table.fourth_pick_points
FROM results_table, pizza_table
WHERE results_table.fourth_pick = pizza_table.id
UNION
SELECT pizza_table.name, results_table.fifth_pick_points
FROM results_table, pizza_table
WHERE results_table.fifth_pick = pizza_table.id

These are the current results:

NAME                POINTS
Caramelized Onion   5
Buffalo Wing        5
Caramelized Onion   5
BM²                 4
asdf                4
Chaco               4
Breakfast           3
Chaco               3
Cheese Bread        3
The Karlyn          2
Caramelized Onion   2
Chicken Bacon Ranch 2
Buffalo Wing        1
Breakfast           1
Breakfast           1

This is what I would like returned:

NAME                POINTS
Caramelized Onion   12
Chaco               7
Buffalo Wing        6
Breakfast           5
BM²                 4
asdf                4
Cheese Bread        3
The Karlyn          2
Chicken Bacon Ranch 2

How do I achieve the results I want?

Answer 1

You will need to use an aggregate but it also appears that you will need to change your query to use UNION ALL between each query:

select name, sum(points) Total
from
(
  SELECT pizza_table.name, results_table.first_pick_points as points
  FROM results_table
  INNER JOIN pizza_table
    ON results_table.first_pick = pizza_table.id
  UNION ALL
  SELECT pizza_table.name, results_table.second_pick_points
  FROM results_table
  INNER JOIN pizza_table
    ON results_table.second_pick = pizza_table.id
  UNION ALL
  SELECT pizza_table.name, results_table.third_pick_points
  FROM results_table
  INNER JOIN pizza_table
    ON results_table.third_pick = pizza_table.id
  UNION ALL
  SELECT pizza_table.name, results_table.fourth_pick_points
  FROM results_table
  INNER JOIN pizza_table
    ON results_table.fourth_pick = pizza_table.id
  UNION ALL
  SELECT pizza_table.name, results_table.fifth_pick_points
  FROM results_table
  INNER JOIN pizza_table
    ON results_table.fifth_pick = pizza_table.id
) d
group by name
order by total desc

See SQL Fiddle with Demo .

Note, I also adjusted your query to use ANSI JOIN syntax ( INNER JOIN ).

Answer 2

// A simple group by should do what you want:

SELECT name, SUM(points) AS points
FROM   table_name
GROUP BY name;

Answer 3

You should use UNION ALL along with a Group by clause at the end - Also added the use of SUM

Working fiddle: http://sqlfiddle.com/#!2/882e3/156

Select name, SUM(points) From(
SELECT pizza_table.name, results_table.first_pick_points as points
FROM results_table, pizza_table
WHERE results_table.first_pick = pizza_table.id
UNION ALL
SELECT pizza_table.name, results_table.second_pick_points
FROM results_table, pizza_table
WHERE results_table.second_pick = pizza_table.id
UNION ALL
SELECT pizza_table.name, results_table.third_pick_points
FROM results_table, pizza_table
WHERE results_table.third_pick = pizza_table.id
UNION All
SELECT pizza_table.name, results_table.fourth_pick_points
FROM results_table, pizza_table
WHERE results_table.fourth_pick = pizza_table.id
UNION All
SELECT pizza_table.name, results_table.fifth_pick_points
FROM results_table, pizza_table
WHERE results_table.fifth_pick = pizza_table.id) x
Group by name