替换以特定字符开头并以正则表达式中的特定字符结尾的字符串

Question

I wanted to replace a string section that starts with a specific character and ends with specific character. At below, I demonstrate test case.

var reg = /pattern/gi;

var str = "asdfkadsf[xxxxx]bb";

var test = str.replace(reg,"") == "asdfkadsfbb"

console.log(test);

Answer 1

This pattern should work for replace anything between brackets (including the brackets):

var reg = /(\[.*?\])/gi;

var str = "asdfkadsf[xxxxx]bb";

var test = str.replace(reg,"") == "asdfkadsfbb"

Answer 2

基于您的示例，这适用：

/\[.*]/gi