函数内部的JavaScript调用函数

Question

I am trying to get the function in a function with argument inside the child function

function firstF (){
  this.childF1 = function($argument){
    // do something + $argument
  }
  this.childF2 = function($argument2){
    // do something + $argument2
  }
}

//Declare a new firstF
var firstFunction = new firstF();
firstFunction.childF1

how do i declare the $argument here?

Answer 1

You do it like this:

var firstFunction = new firstF();
firstFunction.childF1(arghere)

childF1 is a property of your firstF object and that property is a function. So, you call it like a function with parens and you pass the arguments in the parens. You must call it on an already created object of type firstF , not on the firstF function itself.