返回值的类型类似于参数中的类型

Question

Can I create a method so that it returns the value of the type that I specify in parameters? For example:

int i = Settings.Get("count", typeof(int));
string s = Settings.Get("count", typeof(string));
Guid g = Settings.Get("count", typeof(Guid));

Answer 1

public T Get<T> (string value)
{
     //read setting and cast


     //or if you have Setting.Get implementation
     return (T)Settings.Get("count", typeof(T));
}

now you can

int i = Get<int>("count");
string i = Get<string>("count");
Guid i = Get<Guid>("count");

Answer 2

You can do this by making the method generic:

Settings.Get<T>(string name);

Inside the Get method you need to load the value and then cast it to T :

public T Get<T>(string value)
{
    object o = 1; // read setting;
    return (T)o;
}

And then call it:

int i = Get<int>("count");

Answer 3

why don't you try generics like this

   public T Get<T>(string value)
   {
     // do your stuff and cast the value
   }

where T is type