mysql 总工作时间

Question

id     title                              start                    end
1   Doing Coding for this project.  2013-04-02 02:00:00     2013-04-02 04:00:00
2   Doing Coding for this project.  2013-04-02 04:00:00     2013-04-02 06:00:00
3   Doing Coding for this project.  2013-04-02 06:00:00     2013-04-02 06:30:00

I have above MySQL database table record. Now i want to get the total number of hours.

I am developing TimeSheet Management Application and we need to display total working hours with minutes and second of employee. (ie 04:30:00 according to data i share)

what i have tried?

SELECT HOUR(TIMEDIFF(end,start)) AS 'totalHour' but works only for each row not on all records.

I have also tried TIMESTAMPDIFF .

Is this possible?

EDIT

From the answer i have received from people i have tried every single of them but everytime i just get 4 or 4.5000 but it should return 06:30:00 .

Answer 1

The range of HOUR() function is 0 to 23 so it's not correct to use it for total hours in diff.

For single value you could use TIMESTAMPDIFF() like:

SELECT TIMESTAMPDIFF(HOUR, start, end) AS `totalHour` FROM ...

If you want to calculate it for whole project, you have to sum up all time differences and them print it formatted probably with funciton like TIME_FORMAT() which prints hour larger than 24:

If the time value contains an hour part that is greater than 23, the %H and %k hour format specifiers produce a value larger than the usual range of 0..23. The other hour format specifiers produce the hour value modulo 12.

So you can use:

 SELECT TIME_FORMAT( SEC_TO_TIME( SUM( TIME_TO_SEC(end) - TIME_TO_SEC(start))), "%H")
            AS `totalHour`
 FROM ...
 GROUP BY sort_of_project_id

If you need seconds/minutes too (as suggested in comment), use either:

• time_to_sec( <left side of select>)/3600 which will return value like 4.84 hours
• TIME_FORMAT( ..., "%H:%m:%s") which will display 4:38:24

Answer 2

Try this query

SELECT
 id, 
 title, 
 TIME_FORMAT(SEC_TO_TIME(sum(TIME_TO_SEC(TIMEDIFF( end, start)))), "%h:%i") AS diff
FROM 
 tbl1
GROUP BY  
 title

According to the data that you have given answer should be 4:30. Pl cross check in you records.

FIDDLE

Answer 3

Try like this, it will give you the total no of hours:

For Example:

SELECT sum(time_to_sec(timediff(end, start ))/ 3600) AS 'totalHour' from test;

If you run this query for above table you given, it shows the output 4.5 hours.

Hope it will help you.

Answer 4

I already answered in other thread https://stackoverflow.com/questions/44560345/query-is-not-working/44567322#44567322

I just created a temporary table called dataimport

[Table Format][1]

and wrote a query as,

SELECT `EnNo`, work_dt,
        SEC_TO_TIME(sum(TIMESTAMPDIFF(SECOND,login,logout))) as time_worked 
from (
    SELECT `EnNo`, date(`DateTime`) as work_dt, `DateTime` as login
        , coalesce(
              (SELECT MIN(`DateTime`) 
               FROM `dataimport` as b 
               WHERE a.EnNo = b.EnNo 
                 and date(a.`DateTime`) = date(b.`DateTime`)
                 and b.`DateTime` >= a.`DateTime` 
                 and b.`INOUT` = 'E'
              ), now()) AS logout
    FROM `dataimport` AS a 
    WHERE a.`INOUT` = 'S'
) as t
GROUP BY `EnNo`, work_dt

Finally got the output as,

[Output][2]

Hope this is what you are lookin on. [1]: https://i.stack.imgur.com/OEEMe.png [2]: https://i.stack.imgur.com/g6ivm.png

Answer 5

Change your

SELECT HOUR(TIMEDIFF(end,start)) AS 'totalHour'    

to

SELECT sum(TIMESTAMPDIFF(HOUR, end, start)) AS 'totalHour'

Answer 6

SELECT IF(DATE(datetime_end) = DATE(datetime_start), TIMEDIFF(datetime_end,datetime_start), IF(DATEDIFF(datetime_start,datetime_end) > 1, ADDTIME( TIME_FORMAT(CONCAT((DATEDIFF(datetime_start,datetime_end) - 1) * 8,':00:00'), "%H:%i:%s"), ADDTIME( TIMEDIFF(datetime_end,CONCAT(DATE(datetime_end),' 08:00:00')), TIMEDIFF(CONCAT(DATE(datetime_start),' 17:00:00'),datetime_start) ) ) , ADDTIME( TIMEDIFF(datetime_end,CONCAT(DATE(datetime_end),' 08:00:00')), TIMEDIFF(CONCAT(DATE(datetime_start),' 17:00:00'),datetime_start) ) ) ) AS total_working_hrs FROM table