[英]Regex multiline strange behaviour
I have a string like this: 我有一个像这样的字符串:
string text = "ext_bus 0 0/0/3/0.0 side CLAIMED INTERFACE IDE Primary Channel\r\ntarget 0 0/0/3/0.0.0 tgt CLAIMED DEVICE \r\ndisk 0 0/0/3/0.0.0.0 sdisk";
When I do a regex multiline search to get the text in ext_bus third column (0/0/3/0.0) and last column (IDE Primary Channel): 当我进行正则表达式多行搜索以获取ext_bus第三列(0/0/3 / 0.0)和最后一列(IDE Primary Channel)中的文本时:
Regex regExp = new Regex(@"^ext_bus\s*[0-9]+\s*(?<HWPath>\S+).*\s{2,}(?<BusName>.*?)\r?$", RegexOptions.Multiline);
The first group is OK: "0/0/3/0.0" 第一组正常:“ 0/0/3 / 0.0”
But the second group is the next line!: "target 0 0/0/3/0.0.0 tgt CLAIMED DEVICE " 但是第二组是下一行!:“ target 0 0/0/3 / 0.0.0 tgt CLAIMED DEVICE”
How can this be possible with Multiline (only one line), and how can I get the last column (the text at the end of the string after 2 or more whitespaces). 多行(仅一行)如何实现?如何获得最后一列(2个或更多空格之后的字符串末尾的文本)?
The short answer is that it is because the first .*
in your regex matches up till the end of the first line, then the \\s{2,}
matches the newline characters, then the (?<BusName>.*?)
will match all of the second line. 简短的答案是因为正则表达式中的第一个
.*
匹配到第一行的末尾,然后\\s{2,}
匹配换行符,然后(?<BusName>.*?)
将匹配所有第二行。
Multiline
mode means that ^
and $
match the start and end of a line, not just the start and end of the whole string. Multiline
模式意味着^
和$
匹配行的开头和结尾,而不仅仅是整个字符串的开头和结尾。
Remove the .*
and then <BusName>
will be the rest of the text on the line after the whitespace following 0/0/3/0.0
. 删除
.*
,然后<BusName>
将是<BusName>
0/0/3/0.0
后面的空白行之后的其余文本。
Why do you use regex? 为什么使用正则表达式?
You can do it easily with split 您可以轻松地进行拆分
string value = "ext_bus 0 0/0/3/0.0 side CLAIMED INTERFACE IDE Primary Channel\r\ntarget 0 0/0/3/0.0.0 tgt CLAIMED DEVICE \r\ndisk 0 0/0/3/0.0.0.0 sdisk";
char[] delimiters = new char[] {' ' }; // here you can add more seperaors
string[] parts = value.Split(delimiters, StringSplitOptions.RemoveEmptyEntries);
for (int i = 0; i < parts.Length; i++)
{
Console.WriteLine(parts[i]);
}
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