Spring的服务不佳导致400错误请求

Question

I'm having some problems using the Spring restTemplate.

According to API documentation (ONLY FOR PHP) of Rest Service that i'm trying to access. The correct format of POST are:

curl -d "data={\"client_email\":\"steve@martiancraft.com\",\"client_name\":\"Steve Ryner\",\"employee_id\":0,\"service_id\":20216,\"start_date\":\"2012-08-15 09:00:00\",\"note\":\"This is a test.\"}" http://www.setster.com/api/v2/company/7089/appointment?session_token=niab4ptf9mjjem41cooso389f3

to get that response:

{
"statusCode":0,
"statusDescription":"OK",
"data":{
    "status":2,
    "client_id":103352,
    "client_email":"steve@martiancraft.com",
    "client_name":"Steve Ryner",
    "company_id":"7089",
    "employee_id":9862,
    "location_id":"13832",
    "start_date":"2012-08-15 14:00",
    "end_date":"2012-08-15 15:00",
    "length":3600000,
    "note":"This is a test.",
    "service_id":20216,
    "type":"60 Min Swedish",
    "duration_padding":0,
    "repeat_type":0,
    "subservices":"",
    "timezone_dif":-18000,
    "price":"60",
    "custom_fields":"[]",
    "client_phone":"",
    "client_address":"",
    "payment_pending":0,
    "id":171302483
}

}

Here's the important part of my code:

RestTemplate restTemplate = new RestTemplate();

Map<String, String> data = new HashMap<String, String>();

        data.put("client_name", "Alexandre Moraes");
        data.put("client_email", "kalvinmoraes@gmail.com");
        data.put("client_phone", "98065867");
        data.put("employee_id", "0");
        data.put("location_id", "16675"); // Here i have to specify the "Location_ID" because there is more than just one
        data.put("start_date", "2013-05-03 09:15:00");
        data.put("service_id", "18499");

        String result = restTemplate.postForObject("http://setster.com/api/v2/company/6788/appointment/?session_token="+session_token, data, String.class);

        resp.setContentType("text/html;charset=UTF-8");
        PrintWriter out = resp.getWriter();
        out.println(result);

But when i execute that postForObject , the response are a 400 Bad request as if something had sent wrong:

WARNING: POST request for "http://setster.com/api/v2/company/6788/appointment/?session_token=[censored]" resulted in 400 (Bad Request); invoking error handler
WARNING: StandardWrapperValve[setster]: PWC1406: Servlet.service() for servlet setster threw exception

Maybe the format i was sending the data are wrong. But i can't figure out how can i manage that information.

Anyone has any idea of what i'm doing wrong?

Answer 1

In your curl request, the body of your HTTP POST is:

data={\"client_email\":\"steve@martiancraft.com\",\"client_name\":\"Steve Ryner\",\"employee_id\":0,\"service_id\":20216,\"start_date\":\"2012-08-15 09:00:00\",\"note\":\"This is a test.\"}

So your endpoint is expecting a standard HTTP POST with a single string called data, with your serialized JSON. RestTemplate assumes you want to submit this way:

{\"client_email\":\"steve@martiancraft.com\",\"client_name\":\"Steve Ryner\",\"employee_id\":0,\"service_id\":20216,\"start_date\":\"2012-08-15 09:00:00\",\"note\":\"This is a test.\"}

ie, just a JSON object. You won't be able to use RestTemplate for this. Use one of Spring's built-ins for HTTP services.

Answer 2

使用Jackson库-将对象转换为json的简单方法：

ObjectMapper mapper = new ObjectMapper();

mapper.writeValue(resp.getWriter(), data);