正则表达式捕获第一个零
[英]Catch first zero by regex
问题描述
I have a string: 
我有一个字符串：
0012309test07
and I want to find the first zeros and letters. 我想找到第一个零和字母。
00 12309 test 07 00 12309 测试 07
Sure I found letters with /[^\\d]/ , here's the sample . 当然，我发现带有/[^\\d]/字母， 这是示例 。
But how do you catch the first zeros ? 但是，如何捕获前零？
3 个解决方案
解决方案1
4 已采纳 2013-04-04 14:39:57
使用此正则表达式\\b0+|[a-zA-Z]+
解决方案2
1 2013-04-04 14:53:23
使用这种模式
(^(0*))|([a-zA-Z]+)
解决方案3
0 2013-04-04 14:44:22
"0012309test07".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["0012309test07", "00", "12309", "test", "07"] 输出： ["0012309test07", "00", "12309", "test", "07"]
"12309test07".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["12309test07", "", "12309", "test", "07"] 输出： ["12309test07", "", "12309", "test", "07"]
"test07".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["test07", "", "", "test", "07"] 输出： ["test07", "", "", "test", "07"]
"0test07".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["0test07", "0", "", "test", "07"] 输出： ["0test07", "0", "", "test", "07"]
"1test07".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["1test07", "", "1", "test", "07"] 输出： ["1test07", "", "1", "test", "07"]
"test".match(/^(0*)(\\d*)([^\\d]+)(\\d*)$/)
output: ["test", "", "", "test", ""] 输出： ["test", "", "", "test", ""]
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.