[英]how to return null to int method
iam new to programming.iam wrking on a quiz game software. iam是programming.iam上的新手,它使用问答游戏软件。 here i want a count down to be printed as "3,2,1,go...go...go"
在这里,我希望倒数打印为“ 3,2,1,go ... go ... go”
package t2;
import java.util.Scanner;
import java.util.Timer;
import java.util.TimerTask;
public class Stopwatch {
static int interval;
static Timer timer;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int delay = 1000;
int period = 1000;
timer = new Timer();
interval = 3;
System.out.println("3");
timer.scheduleAtFixedRate(new TimerTask() {
public void run() {
System.out.println(setInterval());
}
}, delay, period);
}
private static final int setInterval() {
String go="go...go...go";
if (interval == 2)
{
timer.cancel();
return go;
}
return --interval;
}
}
this says that setInterval() has int as return value.if i place System.out.print("go");
这表示setInterval()具有int作为返回值。如果我放置
System.out.print("go");
in the place of return go;
在
return go;
的地方return go;
it prints go and prints 1 which is out of requirement. 它打印go并打印超出要求的1。 please any buddy can tell me how to do this.
请任何伙伴告诉我该怎么做。
One option would be to change your setInterval() method to return a string like such: 一种选择是更改setInterval()方法以返回如下字符串:
private static final String setInterval() {
String go="go...go...go";
if (interval == 2)
{
timer.cancel();
return go;
}
--interval;
return String.valueOf(interval);
}
Change the return type of setInterval
to object to take advantage of the overloaded println
method and the conditional should check for 1 instead of 2. Also use print
instead of println
to have the output on the same line. 将
setInterval
的返回类型更改为object,以利用重载的println
方法,并且该条件应检查1而不是2。还可以使用print
代替println
来使输出位于同一行。
private static final Object setInterval() {
String go="go...go...go";
if (interval == 1)
{
timer.cancel();
return go;
}
return --interval;
}
Full Example 完整的例子
package t2;
import java.util.Scanner;
import java.util.Timer;
import java.util.TimerTask;
public class Stopwatch {
static int interval;
static Timer timer;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int delay = 1000;
int period = 1000;
timer = new Timer();
interval = 3;
System.out.print("3,");
timer.scheduleAtFixedRate(new TimerTask() {
public void run() {
System.out.print(setInterval() + ",");
}
}, delay, period);
}
private static final Object setInterval() {
String go = "go...go...go";
if (interval == 1) {
timer.cancel();
return go;
}
return --interval;
}
}
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