[英]create list with values between begin and end positions
I have a text file with this format 我有一个这种格式的文本文件
begin end
1 10
25 35
40 50
37 48
... ...
I use these commands to make a list that contains all the values that are between the values from 'begin' and 'end' column 我使用这些命令创建一个列表,其中包含“begin”和“end”列之间值的所有值
x <- read.table("in.txt")
result <- vector("list",486)
for(i in 1:486){
result[[i]] <- c(x[i,1]:x[i,2])
}
lapply(result, write, "out.txt", append=TRUE, ncolumns = 1)
So as result I get a file with 1 column where all the values are on different lines. 因此,我得到一个包含1列的文件,其中所有值都在不同的行上。 Now I want to do something extra.
现在我想做一些额外的事情。
Instead of an input file with only a 'begin' and 'end' column, I have two extra columns, like this: 我只有两个额外的列,而不是只包含'begin'和'end'列的输入文件,如下所示:
begin end A B
1 10 x 0
25 35 x 1
40 50 x 2
37 48 y 0
I want now that the values of these other columns also appear in my output, so that I get something like this 我现在想要这些其他列的值也出现在我的输出中,所以我得到这样的东西
position A B
1 X 0
2 X 0
3 X 0
...
10 X 0
...
40 X 2
41 X 2
...
37 Y 0
How can I change my function, so that the output looks like this? 如何更改我的功能,以便输出看起来像这样?
Here's a data.table
solution: 这是一个
data.table
解决方案:
require(data.table)
DT <- data.table(DF, key=c("A", "B"))
DT[, list(pos = seq(begin, end, by=1)),by=key(DT)]
Here's a base answer: 这是一个基本答案:
lapply(1:nrow(x), function(u) cbind(position=x$begin[u]:x$end[u], x[u,3:4]))
HTH HTH
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