如何将声明的PHP变量作为jQuery选择器获取？

Question

I cannot figure out how to grab a PHP variable and use it as a jQuery variable.

So, I've got for example this variable:

$content = "bla bla bla";

And it is inside a DIV:

div id='contentWrapper'

$content = "bla bla bla";

/div

I know how to grab the ID, class and content (text) of the DIV contentWrapper, but how do I grab $content? I hope I am being clear enough :)

Answer 1

You can't. The PHP runs on the server. The output of the PHP gets sent to the browser. JavaScript runs in the browser. JavaScript has no access to the internals of the script that generated the page it is running in.

You would have to modify the PHP to output the information you want to make available to JS so that it appears in the page.

Answer 2

In the javascript, you can do:

Edit:

Based on @Marc B's comment.

var jsvar = <?php echo json_encode($content); ?>

Answer 3

According to what I believe PHP is server side scripting which is hidden from browser and Jquery script is executed by browser. So to obtain the variable value you need to echo and show your content to browser to complete JQuery. Use the method provided by Jonathan Sampson