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如何投射QList <QObject *> 到QList <ADerivedQObjectClass*>

[英]How to cast QList<QObject *> to QList<ADerivedQObjectClass*>

I can't find a way to cast a QList of QObjects to another QList with another class template. 我无法找到一个方法来投下QListQObjects到另一个QList与其他类模板。 I have a function that creates instances of QObjects and then return a QList . 我有一个创建QObjects实例,然后返回QList的函数。 So my question is, can I cast that QList to another QList of different template class pointers ? 所以我的问题是,我可以将该QList转换为不同模板类指针的另一个QList吗?

My code: 我的代码:

QList<QObject *> DbManager::listVO(QString voname)
{
    DbManager::VOPropertiesJoin(DbManager::VOKeys(obj),VOJOIN_BOTH,"=");
    QList<QObject *> vos;

    QString voquery = "select * from %1";
    voquery = voquery.arg(voname);
    QSqlQueryModel *volist = DbManager::makeSelect(voquery);

    for(int i = 0;i < volist->rowCount();i++){
        QSqlRecord record =volist->record(i);
        QObject *voinstance = DbManager::instantiateVO(voname,record.value(0),record.value(1),record.value(2),record.value(3),record.value(4),record.value(5),record.value(6),record.value(7));
        vos << voinstance;
    }
    return vos;
}

and I want something like this: 我想要这样的东西:

QList<AnyClass*> list = DbManager::listVO("AnyClass");

Thanks for help in advance. 预先感谢您的帮助。

Since what you need at the end is a QList<AnyClass*> , you can try something like this (Assuming AnyClass is derived from QObject ) 由于最后需要的是QList<AnyClass*> ,因此您可以尝试这样的操作(假设AnyClass派生自QObject

Note: I did some modifications to your original code to pass your list by reference since returning a huge list might not that be efficient. 注意:我对原始代码做了一些修改,以通过引用传递列表,因为返回庞大的列表可能并不高效。 I didn't compile the code, but hoping you can figure out what is happening inside this snippet 我没有编译代码,但希望您能弄清楚这段代码中发生了什么

void DbManager::listVO(QString voname, QList<AnyClass*>& listAnyClass)
{
    DbManager::VOPropertiesJoin(DbManager::VOKeys(obj),VOJOIN_BOTH,"=");

    // Initialise list with an empty list
    listAnyClass = QList<AnyClass*>();

    QString voquery = "select * from %1";
    voquery = voquery.arg(voname);
    QSqlQueryModel *volist = DbManager::makeSelect(voquery);

    for(int i = 0; i < volist->rowCount(); i++)
    {
        QObject *voinstance = GetInstance(voname, volist->record(i));

        // Trying to cast into an AnyClass
        AnyClass* pAnyClass = qobject_cast<AnyClass*>(voinstance);

        // If pAnyClass is a valid AnyClass* update your list
        if(pAnyClass)
        {
            listAnyClass.append(pAnyClass);
        }
    }
}

QObject* DbManager::GetInstance(QString sVoname, const QSqlRecord& record)
{
    return DbManager::instantiateVO
    (
        voname,
        record.value(0),
        record.value(1),
        record.value(2),
        record.value(3),
        record.value(4),
        record.value(5),
        record.value(6),
        record.value(7)
    )
}

And after calling DbManager::listVO(QString voname, QList<AnyClass*>& listAnyClass) function, listAnyClass will get populated accordingly. 并且在调用DbManager::listVO(QString voname, QList<AnyClass*>& listAnyClass)函数之后,将相应地填充listAnyClass This is efficient with contrast to returning a list. 与返回列表相比,这是有效的。

Edited: 编辑:

So in a nutshell you want to convert a QList<QObject*> into QList<AnyClass*> . 简而言之,您想将QList<QObject*>转换为QList<AnyClass*> So keep your original code as it is and implement a method like this where you wanna do this conversion: 因此,请保持原始代码不变,并在您要执行此转换的地方实现类似这样的方法:

void ConvertToAnyClassList(const QList<QObject*>& listQObjects, QList<AnyClass*>& listAnyClass)
{
    listAnyClass = QList<AnyClass*>();
    for( int i = 0; i < listQObjects.length(); ++i )
    {
        AnyClass* pAnyClass = qobject_cast<AnyClass*>(listQObjects.at(i));

        if(pAnyClass)
        {
            listAnyClass.append(pAnyClass)
        }
    }
}

And you can call it like this: 您可以这样称呼它:

QList<QObject*> listQObjects = DbManager::listVO("AnyClass");
QList<AnyClass*> listAnyClass;
ConvertToAnyClassList(listQObjects,listAnyClass);

Suppose you have multiple types, so you may want to implement functions for each type like this: 假设您有多种类型,因此您可能需要为每种类型实现如下功能:

ConvertToUserList(listQObjects,listUserObjects);
ConvertToCountryList(listQObjects,listCountryObjects);

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